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lianna [129]
4 years ago
6

How long does it take from the new moon phase to the first quarter phase

Physics
1 answer:
Fynjy0 [20]4 years ago
4 0
The complete cycle of Moon phases takes 29.53 days.

The "First Quarter" has that name because it's one quarter of the time
from one New Moon until the next one.

So that's always close to (0.25 x 29.53) = 7.38 days ... essentially 1 week.
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The power of a bulb is 100 watt .what does it mean​
natita [175]

Answer:

Explanation: 100 watts is a unit of power.

A watt is also the amount of energy being consumed. So the more watts the brighter the light bulb is lit.

3 0
3 years ago
When the temperature of a gas in a balloon is reduced by half, the average kinetic energy of the particles is
Aneli [31]
According to KE = (3/2)kT

reducing temperature, in KELVIN, by half, average KE is reduced by half.
8 0
4 years ago
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Stolb23 [73]

Answer:

a is the answer to the question

3 0
3 years ago
A simple pendulum with a length of 2.23 m and a mass of 6.74 kg is given an initial speed of 2.06 m/s at its equi- librium posit
solniwko [45]

Answer:

a)   T = 2.997 s

b)   K = 14.3 J

c)   φ = 0.444 rad

Explanation:

a) Determine its period

  The pendulum simple’s period is:

 

  T = 2π\sqrt{\frac{l}{g} }

        Where l: Pendulum’s length

                    g = 9.8 m/s2

  T = 2π\sqrt{\frac{2.23}{9.8} }

  T = 2.997 s

b) Total energy

  Initially his total energy is kinetic

  K = \frac{mv^{2} }{2}

  K = \frac{(6.74)(2.06)^{2} }{2}

  K = 14.3 J

c) Maximum angular displacement

  φ = cos^{-1}(1-\frac{E}{mgl} )

  φ = cos^{-1}(1-\frac{14.3}{(6.74)(9.8)(2.23)} )

  φ = 0.444 rad

4 0
3 years ago
An automobile travels on a straight road for 40 km at 30 km/h. It then continues in the same direction for another 40 km at 60 k
Butoxors [25]

Answer:

The average velocity is 40km/h.

Explanation:

The average velocity is \bar{v}=\frac{\Delta x }{\Delta t}, where \Delta x is the distance traveled and \Delta t the time elapsed.

The distance traveled is clearly 80km since it's all done in the same direction, we only need to know the time elapsed. For this we calculate the time elapsed on the first part, and add it to the time elapsed on the second part using always the formula \Delta t=\frac{\Delta x }{v}, where v is the velocity on each part, which is constant.

The time elapsed for the first part is \Delta t_1=\frac{40 km}{30km/h}=\frac{4}{3}h, and the time elapsed for the second part is \Delta t_2=\frac{40 km}{60km/h}=\frac{2}{3}h, giving us a total time of \Delta t_1+\Delta t_2=\frac{4}{3}h+\frac{2}{3}h=2h.

Finally, we can calculate the average velocity: \bar{v}=\frac{80km}{2h}=40km/h.

6 0
3 years ago
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