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Elis [28]
4 years ago
11

If a particle undergoes shm with amplitude 0.21 m, what is the total distance it travels in one period?

Physics
1 answer:
Ymorist [56]4 years ago
7 0
If a particle undergoes simple harmonic motion with an amplitude of 0.21 meters, this means that the maximum displacement of the particle from its resting position is 0.21. For one period, it traveled from its starting position which is twice the amplitude and then back to its original position which is another distance that is twice the amplitude as well. Therefore, the total distance it traveled is 2*amplitude + 2*amplitude = 2*0.21 + 2*0.21 = 0.42 + 0.42 = 0.84 meters.
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3 years ago
a college student produces about 100 kcal of heat per hour on the average what is the rate of energy production and joules
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Given:

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We know that:

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1 year ago
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7 0
3 years ago
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GenaCL600 [577]
<h2>Greetings!</h2>

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The 5 points are certainly appreciated, but I do wish they were Celsius points.


3 0
3 years ago
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