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boyakko [2]
3 years ago
12

If a force of 24 N is applied to an object with a mass of 5 kg, the object will accelerate at _____ m/s2

Physics
1 answer:
Luba_88 [7]3 years ago
7 0
4.8m/s2 according to the formula F=MA
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A 63-kg hiker is climbing the 828-m-tall Burj Khalifa in Dubai. If the efficiency of converting the energy content of the bars i
konstantin123 [22]

Answer:

T_f=5854.76 °C

Explanation:

Given:

mass of hiker, m= 63 kg

height to be climbed, h= 828 m

energy produced by an energy bar, E= 1.10\times 10^6 J

heat capacity of the hiker, c=75.3 J.mol^{-1}.K^{-1}= 4.184 J.kg^{-1}.K^{-1}

initial body temperature of hiker, T_i=36.6 \degree C

<em>The efficiency of converting the energy content of the bars into the work of climbing is 25%, the remaining 75% of the energy released through metabolism is heat released to her body.</em>

We find the energy required for climbing 828 m height:

W=m.g.h

W=63\times 9.8\times 828

W= 511207.2 J

∵Hike eats 2 energy bars= 2\times 1.1\times 10^{6} J

Energy produced= 2.2\times 10^{6} J

Now, according to her efficiency:

Total energy required for producing the work of W= 511207.2 J which is required to climb the given height will be (say, E):

25\% of E= 511207.2

\Rightarrow E= 511207.2\times \frac{100}{25}

E=2044828.8 J

&

Amount of total energy (E) converted into heat(Q) is:

Q=2044828.8-511207.2\\Q=1533621.6J

As we know that:

heat, Q=m.c. (T_f-T_i).................(1)

where:

T_f is the final temperature

Putting respective values in the eq. (1)

1533621.6= 63\times 4.184\times (T_f-36.6)

(T_f-36.6)\approx 5818.16

T_f\approx 5854.76 °C

4 0
3 years ago
A biker starts from rest and reaches a speed of 10 m/s after t travelling with
Natali [406]

Answer:

2m/s^2

Explanation:

we can use this formula to get the answer:

(vf - vi) / t = a

Since vf= 10m/s, vi=0m/s, and t=5

We can just substitute the values into the formula to get the result

that is:

(10 - 0) / 5 = 2m/s^2

6 0
3 years ago
Read 2 more answers
Including them, the mass of the balloon was 1890 kg and had a volume of 11,430 m3 . The balloon floats at a constant height of 6
Monica [59]

Given :

The mass of the balloon was 1890 kg and had a volume of 11,430 m3 .

The balloon floats at a constant height of 6.25m above the ground.

To Find :

The density of the hot air in the balloon.

Solution :

We know,

Volume × ( Density of surrounding air - Density of hot air ) = mass

Putting given values in above equation, we get :

11430\times ( 1.29 - \rho_{hot \ air } ) = 1890\\\\\rho_{hot \ air } = 1.29 - \dfrac{1890}{11430}\\\\\rho_{hot \ air } =  1.125\ kg\ m^3

Therefore, the density of hot air in the balloon is 1.125 kg m³.

4 0
3 years ago
you went to a new planet. you weigh 1/3 as much as you do on earth. is the new planet mass greater than,less than, or equal to e
Nookie1986 [14]
Equal too because the mass never changes
5 0
4 years ago
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A radio has a 1.3 A current. If it has a resistance of 35 Ω, what is the potential difference?
DedPeter [7]

Answer:

22

Explanation:

7 0
3 years ago
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