All categories

2 years ago

If x is a prime number, then x+1 is not a prime number. A counterexample is x=

Mathematics

2 answers:

Veronika [31]2 years ago

8 0

3 is what I think the answer would be. 3 + 1 is 4, 4 is not a prime number, 3 is prime.

Anettt [7]2 years ago

8 0

Answer: The required example is x = 5.

Step-by-step explanation: Given that if x is a prime nu mber, then x+1 is not a prime number.

We are to give a counterexample for this.

Let us consider that

$x=5.$

Then, we know that x is a prime number.

But, we get

$x+1=5+1=6,$ which is not a prime number.

Thus, the required example is x = 5.

You might be interested in

From 13 bagels to 0 bagels

GuDViN [60]

Answer:

LOLL

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Finding the Slope of a Line on a Graph

sukhopar [10]

Answer:

Slope = 2

Step-by-step explanation:

Change in y = 2

Change in x = 1

2/1 = 2

Equation: y = 2x + 3

5 0

2 years ago

Alonso multiplied the fractions 312and (−414) and got a product of −1218. Describe the mistake that Alonso made. What is the cor

weqwewe [10]

Sorry I thought I was gonna understand but I don’t but good luck:) you can do it

8 0

2 years ago

Anthony jogs 11 1/2 miles in 23 mins. If Anthony continues to jog at a steady pace, how many miles will he jog each minute?

frozen [14]

For this case we can raise a rule of three based on Anthony trotting $11 \frac {1} {2}$ miles in 23 minutes.

$11 \frac {1} {2} = \frac {2 * 11 + 1} {2} = \frac {23} {2}$

$\frac {23} {2}$ miles -----------> 23 minutes

x ----------------------------------------> 1minute

$x = \frac {\frac {23} {2} * 1} {23}\\x = \frac {\frac {23} {2}} {23}\\x = \frac {23} {2 * 23}\\x = \frac {1} {2}$

ANswer:

0.5 miles per minute

5 0

2 years ago

Find p and q for which the linear eqn has infinite solutions

jekas [21]

Answer:

p= 2.5

q= 7

Step-by-step explanation:

The lines should overlap to have infinite solutions, slopes should be same and y-intercepts should be same.

Equations in slope- intercept form:

6x-(2p-3)y-2q-3=0 ⇒ (2p-3)y= 6x -2q-3 ⇒ y= 6/(2p-3)x -(2q+3)/(2p-3)

12x-( 2p-1)y-5q+1=0 ⇒ (2p-1)y= 12x - 5q+1 ⇒ y=12/(2p-1)x - (5q-1)/(2p-1)

Slopes equal:

6/(2p-3)= 12/(2p-1)

6(2p-1)= 12(2p-3)

12p- 6= 24p - 36

12p= 30

p= 30/12

p= 2.5

y-intercepts equal:

(2q+3)/(2p-3)= (5q-1)/(2p-1)

(2q+3)/(2*2.5-3)= (5q-1)/(2*2.5-1)

(2q+3)/2= (5q-1)/4

4(2q+3)= 2(5q-1)

8q+12= 10q- 2

2q= 14

q= 7

7 0

2 years ago