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tia_tia [17]
3 years ago
6

Suppose an architect has a drawing of a project he is building. The drawing is 8 wide long by 10 inches long. The finished struc

ture is 64 feet wide by 80 feet long. How many times larger is the actual structure than the drawing?
Mathematics
2 answers:
SIZIF [17.4K]3 years ago
5 0
It is 8 times larger, 8x8=64 and 8x10=80 which is the current length and width of the finished structure
slavikrds [6]3 years ago
5 0
It’s larger by two widths because 8x8 = 64 8x10 = 80
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Determine the area of the figure.
LekaFEV [45]

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base * height / 2

=

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I KNOW IT IT LONG BUT PLEASE HELP ME PLEASE
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In the triangle of ABC, D is a point on AB , AC = 7, AD = 6, and BC = 18. The length of DB could be
Ray Of Light [21]

Answer:

19 > DB > 5

Step-by-step explanation:

In a triangle Δ ABC, AC = 7, and BC = 18.

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Hence, the length of AB will be given by 25 > AB > 11.

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Therefore, 25 > 6 + DB > 11

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8 0
3 years ago
An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach
Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

a)

h(x) = -16x² +vx + h_{o}

here v represent velocity

         h_{o} represent initial height of launch

       

h(x) = -16x² + 192x + 208

b)

h(x) = -16x² + 192x + 208

here a = -16

        b = 192

        c = 208

x = -b/2a

  = -192/2(-16)

  = 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

      = 784ft

e)

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1  

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3 years ago
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Because you go by which is closer to the denominator

8 0
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