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Zielflug [23.3K]

3 years ago

13

What is the meaning of numerical form?

2 answers:

kozerog [31]3 years ago

6 0

Numerical form is an actual number as opposed to a word.

"Seven" is not numerical form.
"7" is numerical form.

Rzqust [24]3 years ago

5 0

The answer should be a number (like 6) not words (like six).

You might be interested in

The equation 2x2 − 12x + 1 = 0 is being rewritten in vertex form. Fill in the missing step. Given 2x2 − 12x + 1 = 0 Step 1 2(x2

Bezzdna [24]

Answer:

Part 1) $2(x-3)^{2}-17=0$ (the missing steps in the explanation)

Part 3) (8, 4); The vertex represents the maximum profit

Part 4) x = 3.58, 0.42

Part 5) x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made

Part 6) 2(x − 7)2 + 118; x = $7

Part 7) The maximum height of the puck is 4 feet. −(x − 4)^2 + 6

Part 8) (x + 3)^2 − 4

Part 9) 2(x − 1)^2 = 4

Part 10) 8(x − 4)^2 + 592

Step-by-step explanation:

Part 1) we have

$2x^{2} -12x+1=0$

Convert to vertex form

step 1

Factor the leading coefficient and complete the square

$2(x^{2} -6x)+1=0$

$2(x^{2} -6x+9)+1-18=0$

step 2

$2(x^{2} -6x+9)+1-18=0$

$2(x^{2} -6x+9)-17=0$

step 3

Rewrite as perfect squares

$2(x-3)^{2}-17=0$

Part 3) we have

$f(x)=-x^{2}+16x-60$

we know that

This is the equation of a vertical parabola open downward

The vertex is a maximum

Convert to vertex form

$f(x)+60=-x^{2}+16x$

Factor the leading coefficient

$f(x)+60=-(x^{2}-16x)$

Complete the squares

$f(x)+60-64=-(x^{2}-16x+64)$

$f(x)-4=-(x^{2}-16x+64)$

Rewrite as perfect squares

$f(x)-4=-(x-8)^{2}$

$f(x)=-(x-8)^{2}+4$

The vertex is the point (8,4)

The vertex represent the maximum profit

Part 4) Solve for x

we have

$-2(x-2)^{2}+5=0$

$-2(x-2)^{2}=-5$

$(x-2)^{2}=2.5$

square root both sides

$(x-2)=(+/-)1.58$

$x=2(+/-)1.58$

$x=2(+)1.58=3.58$

$x=2(-)1.58=0.42$

Part 5) we have

$f(x)=-x^{2}+50x-264$

we know that

The zeros or x-intercepts are the value of x when the value of the function is equal to zero

so

In this context the zeros represent the number of monthly memberships where no profit is made

To find the zeros equate the function to zero

$-x^{2}+50x-264=0$

$-x^{2}+50x=264$

Factor -1 of the leading coefficient

$-(x^{2}-50x)=264$

Complete the squares

$-(x^{2}-50x+625)=264-625$

$-(x^{2}-50x+625)=-361$

$(x^{2}-50x+625)=361$

Rewrite as perfect squares

$(x-25)^{2}=361$

square root both sides

$(x-25)=(+/-)19$

$x=25(+/-)19$

$x=25(+)19=44$

$x=25(-)19=6$

Part 6) we have

$-2x^{2}+28x+20$

This is a vertical parabola open downward

The vertex is a maximum

Convert the equation into vertex form

Factor the leading coefficient

$-2(x^{2}-14x)+20$

Complete the square

$-2(x^{2}-14x+49)+20+98$

$-2(x^{2}-14x+49)+118$

Rewrite as perfect square

$-2(x-7)^{2}+118$

The vertex is the point (7,118)

therefore

The video game price that produces the highest weekly profit is x=$7

Part 7) we have

$f(x)=-x^{2}+8x-10$

Convert to vertex form

$f(x)+10=-x^{2}+8x$

Factor -1 the leading coefficient

$f(x)+10=-(x^{2}-8x)$

Complete the square

$f(x)+10-16=-(x^{2}-8x+16)$

$f(x)-6=-(x^{2}-8x+16)$

Rewrite as perfect square

$f(x)-6=-(x-4)^{2}$

$f(x)=-(x-4)^{2}+6$

The vertex is the point (4,6)

therefore

The maximum height of the puck is 4 feet.

Part 8) we have

$x^{2}+6x+5$

Convert to vertex form

Group terms

$(x^{2}+6x)+5$

Complete the square

$(x^{2}+6x+9)+5-9$

$(x^{2}+6x+9)-4$

Rewrite as perfect squares

$(x+3)^{2}-4$

Part 9) we have

$2x^{2}-4x-2=0$

This is the equation of a vertical parabola open upward

The vertex is a minimum

Convert to vertex form

Factor 2 the leading coefficient

$2(x^{2}-2x)-2=0$

Complete the square

$2(x^{2}-2x+1)-2-2=0$

$2(x^{2}-2x+1)-4=0$

Rewrite as perfect squares

$2(x-1)^{2}-4=0$

$2(x-1)^{2}=4$

The vertex is the point (1,-4)

Part 10) we have

$8x^{2}-64x+720$

This is the equation of a vertical parabola open upward

The vertex is a minimum

Convert to vertex form

Factor 8 the leading coefficient

$8(x^{2}-8x)+720$

Complete the square

$8(x^{2}-8x+16)+720-128$

$8(x^{2}-8x+16)+592$

Rewrite as perfect squares

$8(x-4)^{2}+592$

the vertex is the point (4,592)

The population has a minimum at x=4 years ( that is after 4 years since 1998 )

6 0

3 years ago

my sister and I ate some of a chocolate bar. she ate 3/5 of it and I ate 1/10 of it. how much of the chocolate bar did we eat

sergij07 [2.7K]

3/5 + 1/10 = 7/10.
Hope this helps!:)
~Scarlett

7 0

3 years ago

Read 2 more answers

Name the sets of numbers to which -1/2 belongs

anygoal [31]

A Hope Fully Im Right / Im pretty sure thats the answer

8 0

3 years ago

Hcf of two numbers is 2 and lcm is 54 if one of the number is 27 find the other number

anyanavicka [17]

Answer:

4

Step-by-step explanation:

Given that:

Let the two numbers = a and b

H. C. F of the two numbers = 2

L.C.M of the two numbers = 54

If a = 27 ; b =?

The product of a and b = product of their L. C. M and H. C. F ;

HENCE ;

27 * b = 2 * 54

27b = 108

b = 108/27

b = 4

Hence, second number is 4

7 0

3 years ago

A trapezoid has a height of 6 feet. The measures of the bases are 12 units and 18

Alik [6]

The area of this trapezoid is 90 square feet.

<h3>Explanation : </h3>

Before we know the answer, let's we know the formula first. The formula for count the area of trapezoid is :

$\boxed {\bold {A = \frac {(a+b) \times h}{2}}}$

If :

A = area of trapezoid
a = bottom bases of trapezoid
b = top bases of trapezoid
h = height of trapezoid

Okay, let's we count its :

We know that :

a = bottom bases of trapezoid = 18 feet
b = top bases of trapezoid = 12 feet
h = height of trapezoid = 6 feet

Question : A = area = ... ?

Answer :

$A = \frac {(a+b) \times h}{2} \\ A = \frac {(12+18) \times \cancel6}{\cancel2} \\ A = 30 \times 3 = 90 \: {ft}^{2}$

<u>Subject</u><u> </u><u>:</u><u> </u><u>Mathematics</u>

<u>Keyword</u><u> </u><u>:</u><u> </u><u>Count</u><u> </u><u>The</u><u> </u><u>Area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>shape</u>

8 0

3 years ago