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3 years ago

Tell the measure of the angle in degrees for 1/2

Mathematics

1 answer:

andrew11 [14]3 years ago

5 0

1/2 radian ≈ 28.648°

Multiply by 180°/π to convert from radians to degrees.

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(12x+13)2 hope this helps

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JulsSmile [24]

Answer:

2:10

Step-by-step explanation:

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X^3+3y-xy' = 0 dy/dx = xy^3-xy

Marat540 [252]

Answer:

dy/dx = xy^3-xy =

y = ± √2 = ± 1.4142

x = 0

y = 0

Step-by-step explanation:

Step 1 : Simplify y/d

Step 2 : See below

Step 3 : See below

Pulling out like terms

Trying to factor as a Difference of Squares

Answer:

y = ± √2 = ± 1.4142

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3 years ago

FIRST-PERSON TO ANSWER WILL BE MARKED BRAINLIEST

lara31 [8.8K]

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the Main Street district has 18 buildings

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3 years ago

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Find the area of the curve y= f(x) = x between x = 5 and x = 10

Tems11 [23]

Answer:

the area of the curve y= f(x) = x between x = 5 and x = 10

$A=\frac{75}{2}$

Step-by-step explanation:

Finding the area of the curve y = f(x) = x between x = 5 and x = 10

Using the Area formula

$A=\int _a^b\:f\left(x\right)dx$

As the area of curve lies between x = 5 and x = 10

a = 5, b = 10

so the integral expression becomes

$A=\int _5^{10}xdx$

$\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$A=\left[\frac{x^{1+1}}{1+1}\right]^{10}_5$

$=\left[\frac{x^2}{2}\right]^{10}_5$

$=\frac{1}{2}\left[10^2-5^2\right]$

$=\frac{1}{2}\cdot \:75$

$=\frac{75}{2}$

Therefore, area of the curve y= f(x) = x between x = 5 and x = 10

$A=\frac{75}{2}$

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3 years ago