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aleksklad [387]
3 years ago
12

Arlo invested $4000 in an account that earns 5.5% interest, compounded annually. The formula for compound interest is A(t)=P(1+i

)^t. How much did Arlo have in the account after 4 years?
Mathematics
2 answers:
alexira [117]3 years ago
6 0

Answer:

$ 4955.30 ( approx )

Step-by-step explanation:

The formula for compound interest is,

A(t)=P(1+i)^t

Where, P is the principal amount,

i is the rate per period,

t is the number of periods,

Here, P = $ 4000,

i = 5.5% = 0.055

t = 4 years,

By substituting the values,

The amount in the account after 4 years would be,

A=4000(1+0.055)^4=4000(1.055)^4=4955.2986025\approx \$4955.30

USPshnik [31]3 years ago
4 0

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases} \\\\\\ A=4000\left(1+\frac{0.055}{1}\right)^{1\cdot 4}\implies A=4000(1.055)^4\implies A\approx 4955.2986

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Step-by-step explanation:

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Fluffy the cat is 3 years older than Scuffy the dog. This means that

x = y + 3 - - - - - -- - - - - 1

Six less than five times Scruffy's age is one more than three times Fluffy's age. This means that

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Substituting equation 1 into equation 2, it becomes

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We should know that, the system of linear equations can be treated as matrices, i.e: we can modify or make any operations provide that we must apply the same operation for all terms of each equation.

Given:  the solution for the following system is (2,9)

Px + Qy = R  ⇒(1)

Tx + Uy = V  ⇒(2)

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<u>System A)</u>  Px + Qy = R

                  (P+T)x + (Q+U)y = R+V  ⇒(3)

So, By summing (1) and (2) we will get the equation (3)

So, system A has the same solution (2,9)

<u>System B)</u> Px + Qy = R

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By multiplying equation (2) by 2 and add with equation (1), we will get:

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Which is not the same as equation (4)

So, system B has not the same solution (2,9)

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So, system C has the same solution of (2,9)

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So, system D has not the same solution of (2,9)

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