Hey there!:
The fractional saturation y is defined as :
y = [ L ] / Kd + [ L ]
where :
[ L ] = concentration of binding ligand
Kd = 400 nm
Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.
Explanation :
Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.
In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.
We are taking the value of standard reduction potential form the standard table.
![E^0_{[Ag^{+}/Ag]}=+0.80V](https://tex.z-dn.net/?f=E%5E0_%7B%5BAg%5E%7B%2B%7D%2FAg%5D%7D%3D%2B0.80V)
![E^0_{[Cu^{2+}/Cu]}=+0.34V](https://tex.z-dn.net/?f=E%5E0_%7B%5BCu%5E%7B2%2B%7D%2FCu%5D%7D%3D%2B0.34V)
In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.
The balanced two-half reactions will be,
Oxidation half reaction (Anode) : 
Reduction half reaction (Cathode) : 
Thus the overall reaction will be,

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.
Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.
Using accurate measurements, using pure chemicals and performing the reaction under the most ideal conditions is important to get a valuable percent yield.
<h3>How we calculate the percent yield?</h3>
Percent yield of any chemical reaction is define as the ratios of the actual yield to the theoretical yield of the product and multiply by the 100.
To get the high percent yield or actual yield of any reaction, we have to perform the reaction under ideal condition because if we not use the standard condition then we get the low rate of reaction. Reactants should be present in the pure form as impurity make unwanted products and reduce the productivity of main product and accurate amount of reactants also important for the spontaneous reaction.
Hence, options (a), (b) & (c) are correct.
To know more about percent yield, visit the below link:
brainly.com/question/8638404
Answer:
Explanation:
Seven of these isomers having similar pKa values are as follows
1) CH₃ -CH(CH₃)-CH(NO₂)-CH₃
2 ) CH₃ -(CH₂)-CH(NO₂)-CH₂-CH₃
3 ) CH₃ -CH₂-CH₂-CH₂-CH₂-NO₂
4 ) CH₃ -CH₂-CH₂-CH(NO₂)-CH₃
5 )CH₃ -CH(CH₃)(NO₂)-CH₂-CH₃
6 ) CH₃ -CH(CH₃)-CH₂-CH₂-NO₂
7)CH₃ -CH₂-CH₂-CH(CH₃)-NO₂
CH₃-C(CH₃)₂-NO₂
The last isomer has different PKa value because of tertiary carbon attached to nitro group.
A scientific control is an experiment or observation designed to minimize the effects of variables other than the independent variable.