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tigry1 [53]
3 years ago
8

What is the molecular weight of a gas that diffuses through a porous membrane 2.17 times faster than Xe?

Chemistry
1 answer:
vivado [14]3 years ago
8 0

Answer: The molecular weight of the gas 28. The gas is probably N2

Explanation:Please see attachment for explanation

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Why is carbon dioxide nonpolar?
vovikov84 [41]
CO2<span> is a linear molecule and the Oxygen (O) atoms on each end are symmetrical. Polarity results from an unequal sharing of valence electrons. Because of this symmetry there is no region of unequal sharing and </span>CO2<span> is a</span>nonpolar<span> molecule</span>
8 0
3 years ago
An excess of Ba(No3)2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4.determine The concentration in moles per litre
Wewaii [24]
Chemical reaction: Ba(NO₃)₂ + H₂SO₄ → BaSO₄ + 2HNO₃.
V(H₂SO₄) = 250 mL ÷ 1000 mL/L = 0,25 L.
m(BaSO₄) = 0,55 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,55 g ÷ 233,38 g/mol.
n(BaSO₄) = 0,00235 mol.
From chemical reaction: n(BaSO₄) : n(Ba(NO₃)₂) = 1 : 1.
n(Ba(NO₃)₂) = 0,00235 mol.
c(Ba(NO₃)₂) = n(Ba(NO₃)₂) ÷ V.
c(Ba(NO₃)₂) = 0,00235 mol ÷ 0,25 L.
c(Ba(NO₃)₂) = 0,0095 mol/L.
7 0
3 years ago
If 10.0 g water at 0.0°C is mixed with 20.0 g of water at 30.0°C what is the final temperature of the mixture?
Bond [772]

Answer:

1.67 gradius Celcius

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

7 0
2 years ago
What is the wavelength of light with 2.89 x 10-19 J of energy? (The speed of
Alika [10]

Let's see

\\ \rm\rightarrowtail E=hv

\\ \rm\rightarrowtail E=\dfrac{hc}{\lambda}

  • lambda is wavelength
  • h is Planck constant
  • c is velocity of sound in air
  • E in energy

\\ \rm\rightarrowtail \lambda=\dfrac{hc}{E}

\\ \rm\rightarrowtail \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{2.89\times 10^{-19}}

\\ \rm\rightarrowtail \lambda=6.878\times 10^{-7}m

\\ \rm\rightarrowtail \lambda=68.8\mu m

3 0
1 year ago
Calculate the molality of a solution formed by adding 6.30 g NH4CL to 15.7 g of water
babymother [125]

Answer:

Molality = 7.5 mol/kg

Explanation:

Given data:

Mass of NH₄Cl = 6.30 g

Mass of water = 15.7 g (15.7/1000 =0.016 kg)

Molality = ?

Solution:

Formula of molality:

Molality = Moles of solute / mass of solvent in gram

Now we will first calculate the number of moles of solute( NH₄Cl )

Number of moles = mass/ molar mass

Molar mass of  NH₄Cl = 53.491 g/mol

Number of moles = 6.30 g/  53.491 g/mol

Number of moles =  0.12 mol

Now we will calculate the molality.

Molality = Moles of solute / mass of solvent in gram

Molality =  0.12 mol / 0.016 kg

Molality = 7.5 m

or        (m=mol/kg)

Molality = 7.5 mol/kg

6 0
3 years ago
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