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3 years ago

What is the molecular weight of a gas that diffuses through a porous membrane 2.17 times faster than Xe?

Chemistry

1 answer:

vivado [14]3 years ago

8 0

Answer: The molecular weight of the gas 28. The gas is probably N2

Explanation:Please see attachment for explanation

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What mass (in mg) does 2.63 moles of nickel have?

Romashka-Z-Leto [24]

Atomic mass Nickel ( Ni) = 58.69 a.m.u

1 mole ------------- 58.69 g
2.63 moles -------- ??

2.63 x 58.69 / 1 => 154.3547 g

1 g ------------- 1000 mg
154.3547 g ---- ??

154.3547 x 1000 / 1

=> 154,354.7 mg

6 0

3 years ago

What are the correct coefficients when this chemical equation is<br> balanced? *<br> P4 + 02 P2O5

finlep [7]

Answer:

What are the correct coefficients when this chemical equation is

balanced? *

P4 + 02 P2O5

Explanation:

For this reaction we have a combination reaction. Balancing Strategies: This combination reaction is a lot easier to balance and if you can get an even number of oxygen atoms on the reactants side of the equation.

3 0

2 years ago

What volume of a 2.0M NaOH(aq) is needed to completely neutralize 24 milliliters of 0.5M HCl(aq)?

borishaifa [10]

Answer:

$V_{base}=6.0mL$

Explanation:

Hello there!

In this case, by considering that the reaction between sodium hydroxide and hydrochloric acid is in a 1:1 mole ratio of these two reactants, we are able to use the following equation relating the concentration and volume of each one:

$M_{acid}V_{acid}=M_{base}V_{base}$

In such a way, by solving for the volume of the base, we will obtain:

$V_{base}=\frac{M_{acid}V_{acid}}{M_{base}} \\\\V_{base}=\frac{0.5M*24mL}{2.0M}\\\\V_{base}=6.0mL$

Regards!

8 0

3 years ago

The metal tantalum becomes superconducting at temperatures below 4.483 K. Calculate the temperature at which tantalum becomes su

masha68 [24]

Answer:

The correct answer is "-268.667°C".

Explanation:

Given:

Temperature,

= 4.483 K (below)

Now,

The formula of temperature conversion will be:

⇒ $T(^{\circ} C)=T(K)-273.15$

By putting the values, we get

⇒ $=4.483-273.15$

⇒ $=-268.667^{\circ} C$

Thus the above is the correct answer.

3 0

3 years ago

Suppose that Daniel has a 3.00 3.00 L bottle that contains a mixture of O 2 O2 , N 2 N2 , and CO 2 CO2 under a total pressure of

Alenkinab [10]

Answer:

Partial pressure O₂ → 2.74 atm

Explanation:

Let's analyse the data given:

Volume → 3L

In the bottle there is a mixture of gases that contains, O₂, N₂ and CO₂.

Total pressure is 4.80 atm

Let's apply the Ideal Gases Law to determine the total moles of the mixture

P . V = n . R. T

4.80 atm . 3L = n . 0.082 . 273K

n = 4.80 atm . 3L / 0.082 . 273K → 0.643 moles

We apply the concept of mole fraction:

Mole fraction of a gas X = moles of gas X / Total moles

Mole fraction of a gas X = Partial pressure X / Total pressure

In a mixture, sum of mole fraction of each gas = 1

We determine mole fraction of N₂ → 0.230 / 0.643 = 0.357

We determine mole fraction of CO₂ → 0.350 atm / 4.80 atm = 0.0729

1 - mole fraction N₂ - mole fraction CO₂ = mole fraction O₂

1 - 0.357 - 0.0729 = 0.5701 → mole fraction O₂

We replace in the formula: Mole fraction O₂ = Partial pressure O₂ / 4.80 atm

0.5701 . 4.80 atm = Partial pressure O₂ → 2.74 atm

5 0

3 years ago

Read 2 more answers