Which mountain range was once the tallest in the world?

Explain where the radiant energy comes from and how that energy is used in the food web. (Your answer should be three complete s

Fudgin [204]

Answer:

j

Explanation:

Radiant energy comes from the sun. In the food chain it gives energy to plants which makes them grow. The plants store this energy and give it to the animals that consume them as the food chain goes on.

7 0

3 years ago

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If i start with 46 ml of 1.25 m hcl and dilute it to a volume of 250 ml, what is the concentration of my final solution

ikadub [295]

Equation: M1V1 = M2V2

Where M = concentration & V = volume

Step 1: Write down what is given and what you are trying to find

Given: M1 = 1.25M, V1 = 46mL, and V2 = 250mL
Find: M2

Step 2: Plug in the values into the equation

M1V1 = M2V2
(1.25M)(46mL) = (M2)(250mL)

Step 3: Isolate the variable (Divide both sides by 250mL so M2 is by itself)

(1.25M)(46mL) / (250mL) = M2

Answer: M2 = 0.23M

7 0

3 years ago

A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO4. (a) Write the balanced chemical equ

NISA [10]

Answer:

a) 2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂

b) Ni(OH)₂

c) KOH

d) 0.927 g

e) K⁺=0.067 M, SO₄²⁻=0.1 M, Ni²⁺=0.067 M

Explanation:

a) The equation is:

2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂ (1)

b) The precipitate formed is Ni(OH)₂

c) The limiting reactant is:

$n_{KOH} = V*M = 100.0 \cdot 10^{-3} L*0.200 mol/L = 0.020 moles$

$n_{NiSO_{4}} = V*M = 200.0 \cdot 10^{-3} L*0.150 mol/L = 0.030 moles$

From equation (1) we have that 2 moles of KOH react with 1 mol of NiSO₄, so the number of moles of KOH is:

$n = \frac{2}{1}*0.030 moles = 0.060 moles$

Hence, the limiting reactant is KOH.

d) The mass of the precipitate formed is:

$n_{Ni(OH)_{2}} = \frac{1}{2}*n_{KOH} = \frac{1}{2}*0.020 moles = 0.010 moles$

$m = n*M = 0.010 moles*92.72 g/mol = 0.927 g$

e) The concentration of the SO₄²⁻, K⁺, and Ni²⁺ ions are:

$C_{K^{+}} = \frac{2*\frac{1}{2}*n_{KOH}}{V} = \frac{0.020 moles}{0.300 L} = 0.067 M$

$C_{SO_{4}^{2-}} = \frac{\frac{1}{2}*n_{KOH + (0.03 - 0.01)}}{V} = \frac{0.030 moles}{0.300 L} = 0.1 M$

$C_{Ni^{2+}} = \frac{0.020 moles}{0.300 L} = 0.067 M$

I hope it helps you!

5 0

4 years ago

Summarize how chemical energy is formed from light energy

Eddi Din [679]

I believe that the answer to the question provided above is light energy is trapped, and by certain enzymes then transformed to chemical energy.
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.

3 0

3 years ago

Reduction of aqueous nitrous acid hno2 to gaseous nitric oxide no in acidic aqueous solution. be sure to add physical state symb

telo118 [61]

Reduction is only one half of the reaction of a redox (reduction-oxidation reaction). It is characterized by the reduction of oxidation number or the gain of electrons. So, you would expect the reaction to have moles of electrons in the reactant side to depict gaining of electrons. The reduction reaction is as follows:

<em>HNO₂ + e⁻ --> NO</em>

Why only 1 e-? Compute the oxidation number of N in the reactant side.
1+x+2(-2) = 0; x = +3
Then, compute the oxidation number of N in the product side.
x -2 = 0; x = +2

So, there is a difference of 1 electron. Hence, 1e-.

5 0

4 years ago