Explanation:
Given;
Number of moles of the elements = 3.8moles
Molar mass of Gold = 196.966g/mol
Molar mass of Magnesium = 24.3g/mol
Molar mass of Tin = 118.710g/mol
Molar mass of Bromine = 79.904g/mol
Mass = number of moles x molar mass
Mass of Gold = 3.8 x 196.966 = 748.5g
Mass of Magnesium = 3.8 x 24.3 = 92.3g
Mass of Tin = 3.8 x 118.710 = 451.1g
Mass of Bromine = 3.8 x 79.904 = 303.6g
T(1/2)=1/(k[NO2])
[NO2]=1/(kt(1/2))
[NO2]=1/(0.54M-1 s-1*22s) seconds cancel
[NO2]=1/11.88=0.0842
inital mole= 0.0842*volume(2.5)=0.210 mols
Answer:
The answer to your question is: 1.5 M
Explanation:
Data
MW NaOH = 40 g/mol
mass = 30 g
V = 500 ml
Molarity (M) = ?
number of moles = n
Formula
M = n/V(l)
Process
40 g ------------------- 1 mol
30 g --------------------- x
x = (30)(1)/40
x = 0.75 mol
Volume
1000 ml ----------------- 1 l
500 ml ---------------- x
x = (500)(1) / 1000
x = 0.5 l
Molarity = 0.75 / 0.5
= 1.5 M
Answer:
Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements
