Answer:
The smallest ballon is the ballon X
Explanation:
It is possible to answer this question by using Graham's law:
Where v is the speed of effusion and MW is molar weight of each compound.
This equation is showing that speed is inversely related to the square root of its molar mass. As carbon dioxide has a bigger MW than carbon monoxide, the speed of effusion of carbon dioxide is lower doing its ballon biggest than carbon monoxide ballon, thus: <em>The smallest ballon is the ballon X</em>
<em></em>
I hope it helps!
Answer:
c. when the meniscus is between marks, estimate the reading to the nearest tenth of a division (ie, estimate to 0.01 mL if buret has 0.1 ml divisions)
Explanation:
When we put a liquid in a pipette, we can see that the surface of that liquid will have a curve. This curve is called the meniscus and it has the correct volume that an aqueous solution has. However, for this, it is necessary that the meniscus is observed at eye level and that its edges and center are clearly visible.
Answer:
Explanation:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
The reaction above is a typical combustion reaction which are very common with hydrocarbons. Combustion occurs in the presence of oxygen to product carbon dioxide and water. The purpose of this reaction is to transform chemical energy into useful heat energy. Most times, the oxygen used is always in excess of the hydrocarbon reacting with it.
Answer:
TY and I like the country studies.
Explanation:
ok bye por a mathmu n bye for now and hope you have patience.
Hey there!:
<span>Reaction stoichiometry :
</span>
Number of moles NaHCO3 :
Molar mass NaHCO3 = <span>84.007 g/mol
</span>
n = m / mm
n = 2.50 / 84.007
n = 0.0297moles of NaHCO3
2 NaHCO3 + H2SO4 = Na2SO4 + 2 CO2 + 2 H2O
2 moles NaHCO3 ----------------- 1 mole H2SO4
0.0297 moles NaHCO3 ----------- moles H2SO4
moles H2SO4 = 0.0297 * 1 / 2
moles H2SO4 = 0.0297 / 2
= 0.01485 moles of H2SO4
Therefore:
Molarity ( H2SO4 ) = moles H2SO4 / volume
0.600 M = 0.01485 / V
V = 0.01485 / 0.600
V = 0.02475 L of H2SO4
hope this helps!