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swat32
3 years ago
12

If there are 17 green marbles in a jar of 65 marbles, what is the probability of drawing 2 green marbles at random without repla

cement?
A. 33/129

B. 17/260

C. 17/65

D. 33/65
Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

Option b) \frac{17}{260}

Step-by-step explanation:

We are given the following information in the question:

Total number of marbles = 65

Number of green marbles = 17

We have to find the probability of drawing 2 green marbles at random without replacement.

Formula:

Probability = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

\text{P(Drawing 2 green marbles at random without replacement)} = \\\text{Probability of drawing }1^{st} \text{ green marble}\times \text{Probability of drawing }2^{nd} \text{ green marble}

\text{Probability of drawing }1^{st} \text{ green marble} = \displaystyle\frac{17}{65}\\\\\text{Probability of drawing }2^{nd} \text{ green marble} = \displaystyle\frac{16}{64}

\text{P(Drawing 2 green marbles at random without replacement)} =\displaystyle\frac{17}{65}\times \frac{16}{64}=\frac{17}{260}

Option b) \frac{17}{260}

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