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a_sh-v [17]
3 years ago
13

Determine the sine, cosine, and tangent of the angle.

Mathematics
2 answers:
lana [24]3 years ago
5 0

Answer: Option d.

Step-by-step explanation:

You need to use the trigonometric identities:

sin\theta=\frac{opposite}{hypotenuse}\\\\cos\theta=\frac{adjacent}{hypotenuse}\\\\tan\theta=\frac{opposite}{adjacent}

Identify the opposite side, the adjacent side and the hypotenuse in the right triangle:

opposite=9\\adjacent=12\\hypotenuse=15

Substituting these values into the corresponding identity, you get:

sin\theta=\frac{9}{15}\\\\cos\theta=\frac{12}{15}\\\\tan\theta=\frac{9}{12}

Cloud [144]3 years ago
4 0

Answer:

The correct answer is option d

Step-by-step explanation:

From the given figure we can see that, a right angled triangle.

<u>Points to remember </u>

Sinθ = Opposite side/Hypotenuse

Cosθ = Adjacent side/Hypotenuse

Tanθ = Opposite side/Adjacent side

Let the angle be θ

<u>To find sine, cosine, and tangent  </u>

Sinθ = Opposite side/Hypotenuse = 9/15

Cosθ = Adjacent side/Hypotenuse = 12/15

Tanθ = Opposite side/Adjacent side = 9/12

The correct answer is Option d

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How many different triangles can you make with the following conditions: angles measuring 45 degrees and 90 degrees and an INCLU
kotykmax [81]

Answer:

One

Step-by-step explanation:

Clearly, one triangle can be constructed as the angles 45 and 90 do not exceed 180 degrees. (so "None" is not correct)

To show that only one such triangle exists, you can apply the Angle-Side-Angle theorem for congruence.

Since one triangle can be constructed, it remains to be shown that no additional triangle that is not congruent to the first one can be created: I will use proof by contradiction. Let a triangle ABC be constructed with two angles 45 and 90 degree and one included side of length 1 inch. Suppose, I now construct a second triangle that is different from the first one but still has the same two angles and included side. By applying the ASA theorem which states that two triangles with same two angles and one side included are congruent, I must conclude that my triangle is congruent to the first one. This is a contradiction, hence my original claim could not have been true. Therefore, there is no way to construct any additional triangle that would not be congruent with the first one, and only one such triangle exists.

3 0
3 years ago
Wat the answer for this I am going crazy
Lorico [155]
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4 0
3 years ago
Which expression shows how 6 • 45 can be rewritten using the distributive property?. A. 6 • 40 + 6. B. 6 • 4 + 6 • 5. C. 6 • 40
svlad2 [7]
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Option C.
5 0
3 years ago
Read 2 more answers
Two more than the quotient of a number and 6<br> is equal to 8
xxTIMURxx [149]

Answer:

36

Step-by-step explanation:

"Two more" = + 2

"quotient of a number and 6" = n/6

"equal to 8" = = 8

Set the equation:

n/6 + 2 = 8

Isolate the variable n. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 2 from both sides.

n/6 + 2 (-2) = 8 (-2)

n/6 = 8 - 2

n/6 = 6

Isolate the variable n. Multiply 6 to both sides.

(n/6)(6) = (6)(6)

n = 6 * 6

n = 36

36 is your answer.

~

3 0
3 years ago
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Dafna11 [192]

Answer:

Un teorema tematico o un teorema matematico?

Step-by-step explanation:

4 0
3 years ago
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