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Digiron [165]
3 years ago
14

What is the quotient of 4/11 and 12/7?

Mathematics
2 answers:
IrinaK [193]3 years ago
7 0

Answer:

\frac{4}{33}.

Step-by-step explanation:

Given  : \frac{4}{11} and \frac{12}{7}

To find : What is the quotient.

Solution : We have given \frac{4}{11} and \frac{12}{7}.

According to question :

Quotient of \frac{4}{11} and \frac{12}{7} = \frac{4}{\frac{11}{\frac{12}{7}}}.

We can write

\frac{4}{\frac{11}{\frac{12}{7}}} = \frac{4}{11}*\frac{7}{12}.

\frac{4}{11}*\frac{7}{12}

\frac{28}{132}.

On dividing both number by 4

\frac{4}{33}.

Therefore,  \frac{4}{33}.

Juli2301 [7.4K]3 years ago
6 0

Answer: C. 7/33

Step-by-step explanation: First you have to multiply 4/11 to the reciprocal of 12/7. After that you have to simplify 28/132 to 7/33

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Three cubes of the same metal, whose edges are 6, 8, 10 cm are meltedand formed into a single cube. Find the diagonal of the sin
allochka39001 [22]

Answer: 12√2 cm

<u>Step-by-step explanation:</u>

Cube 1: V = 6³ = 216

Cube 2: V = 8³ = 512

Cube 3: <u>V = 10³ = 1000</u>

New Cube: V = 1728

1728 = s³

12 = s

So, each side of the new cube is 12 cm.

Use Pythagorean Theorem to find the length of the diagonal:

12² + 12² = diagonal²

144 + 144 = diagonal²

288 = diagonal²

√288 = diagonal

12√2 = diagonal


3 0
3 years ago
Find the Inverse of 3x^3-1=y
Anika [276]
y = 3x^{3} - 1
x = 3y^{3} - 1
3y^{3} = x + 1
y^{3} = \frac{x + 1}{3}

y = \sqrt[3]{\frac{x + 1}{3}}
5 0
3 years ago
What is a formula for the nth term of the given sequence? 20,23, 26...​
lord [1]

Answer:

17 + 3n

Step-by-step explanation:

20, 23,26 ..............

This is an arithmetic series

First term = a = 20

Common difference = second term -  first term

                               d = 23 - 20 = 3

nth terms = a + (n-1)*d

               = 20 + (n -1) *3

               = 20 + n*3 - 1*3

              = 20 + 3n - 3

               = 20 - 3 + 3n

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6 0
3 years ago
Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

3 0
2 years ago
What are three collinear points in the figure below?
algol [13]

Answer:

B. W,V,Z

Step-by-step explanation:

Collinear points are two more points in the same plane that lie in a straight line.

From the diagram, Z is the intersection of the two diagonals of quadrilateral VXWY.

The points V, Z and W lie along the same diagonal, hence they are collinear.

The point y, Z, and X also lie along the same diagonal, these are also collinear.

The correct choice is B

7 0
3 years ago
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