Ask question

Ask question

All categories

3 years ago

7

One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant rate from 8 p.m. to midnight. At mi

dnight the temperature was −16.8 degrees. What was the temperature at 9 p.m.?

1 answer:

Elena L [17]3 years ago

4 0

-16.8 = m(4)

-16.8 / 4 = -4.2

So the constant rate is -4.2.

Hope this Helps!!

You might be interested in

Which equation represents a proportional relationship?

bonufazy [111]

It's the first one. y = 3x
proportional means they are just some multiple of the other.

4 0

3 years ago

Read 2 more answers

32% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

Tems11 [23]

Answer:

a) $P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

b) $P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

c) $P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.32)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

Part b

$P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]$

$P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211$

$P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

Part c

$P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264$

$P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218$

$P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123$

$P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

6 0

3 years ago

olya-2409 [2.1K]

Answer:

home team

.............................................................................................

8 0

2 years ago

Read 2 more answers

Write an equation of a line that passes through each pair of points. (5,7),(-8,-4)

tester [92]

Answer:

Y=11/13x+36/13

Hope this helps

Mark brainliest :)

8 0

2 years ago

Read 2 more answers

Jordan's mom bought 777 packs of juice boxes for the team to drink after practice. Each pack had 888 boxes of juice. After the t

skad [1K]

Answer:

397047

Step-by-step explanation:

Multiply 777x888=689976

subtract 292929 from 689976

answer is 397047

3 0

2 years ago