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DerKrebs [107]
4 years ago
14

Solve the following quadratic equation for x by completing the square and solve x^2-8x=-65​

Mathematics
1 answer:
Licemer1 [7]4 years ago
7 0

Answer:

x= 4-7i  x= 4+ 7i

Step-by-step explanation:

step 1 : make equation = 0

x^{2} - 8x + 65 = 0

step 2 : solve for x [ using the quadratic equation]

ie :     x = -b ± \sqrt{b^{2}-4ac} / 2a

so it will look like this

x= -(-8) ± \sqrt{(-8)^{2} - 4(1)(65)} /2(1)

when you simplify you wont be able to root the -196 so you will have to separate the roots

x = 8 ±( \sqrt{-1} )( \sqrt{196}) / 2

now there is a rule for negative roots whereby  \sqrt{-1} is equivalent to i so now you will change \sqrt{-1} into i

Simplify \sqrt{196}

which will give you 14

now place all the new values into the formula

8 ± 14i /2

you can then further simplify to  

4 ± 7i

step 3 : separate

this will give you the final answer of

x= 4 + 7i   x= 4- 7i

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Answer:

a) 0.3125 per hour

b) 2.225 hours

c) 8.9 hours

d) 12.1 hours

e) 80%

Step-by-step explanation:

Given that:

mean time = 3.2 hours, standard deviation (σ) = 2 hours

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a) The average number of jobs waiting for service (μ)= 1/ mean time = 1/ 3.2 = 0.3125 per hour

b) The average time a job waits before the welder can begin working on it (L) is given by:

L=\frac{\lambda^2\sigma^2+(\lambda/\mu)^2}{2(1-\lambda/\mu))} =\frac{0.25^2*0.2^2+(0.25/0.3125)^2}{2(1-0.25/0.3125)}=2.225\ hours

c) The average number of hours between when a job is received and when it is completed (Wq) is given as:

W_q=\frac{L}{\lambda}=2.225/0.25=8.9\ hours

d) The average number of hours between when a job is received and when it is completed (W) is given as:

W=W_q+\frac{1}{\mu} =8.9+\frac{1}{0.3125}=12.1 \ hours

e) Percentage of the time is Gubser's welder busy (P) is given as:

P=\frac{\lambda}{\mu}=0.25/0.3125=0.8=80\%

4 0
3 years ago
Please help me with this assignment, I will reward 100 points for an honest and fair answer.
meriva
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answer
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