Answer:
a) 0.3125 per hour
b) 2.225 hours
c) 8.9 hours
d) 12.1 hours
e) 80%
Step-by-step explanation:
Given that:
mean time = 3.2 hours, standard deviation (σ) = 2 hours
The mean service rate in jobs per hour (λ) = 2 jobs/ 8 hour = 0.25 job/hour
a) The average number of jobs waiting for service (μ)= 1/ mean time = 1/ 3.2 = 0.3125 per hour
b) The average time a job waits before the welder can begin working on it (L) is given by:

c) The average number of hours between when a job is received and when it is completed (Wq) is given as:

d) The average number of hours between when a job is received and when it is completed (W) is given as:

e) Percentage of the time is Gubser's welder busy (P) is given as:

Order from least to greatest
-9/2, - 3, 1/2, sqrt(6), 4.2
answer
D.-9/2, - 3, 1/2, sqrt(6), 4.2
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sqrt(10) is irrational number and real numbers
answer is B.irrational number and real numbers
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square root (81) = 9
square root (100) = 10
square root (93) is between 9 and 10
so answer
9< sqrt(93) < 10
2log10(2vx2) is the answer
No, less than half of the applicants got an interview. 1/2 of the applicants would be 24 that would need to be interviewed.
To calculate the percentage: 22/48 x 100. This gives you 45.8% got interviewed.