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AfilCa [17]
2 years ago
6

Simplify the expression below as much as possible (6-i)+(4+2i)-(-2+i)

Mathematics
1 answer:
Luba_88 [7]2 years ago
4 0

Answer:

=6-i+4+2i+2-i

=6+4+2+2i-i-i

=12+2i-2i

=12

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Need ASAP
Arlecino [84]

Answer:

1. x = 2

2. x = 21

Step-by-step explanation:

Hope this helps

6 0
2 years ago
Julio's father is 4 times as old as Julio. The sum of their ages is no less than 55.
seropon [69]
Call (F) the age of the father and (J) the age of Julio

The F & J are related in this way: F=4J

 Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.

Algebraically that is: F + J ≥ 55

You can substitute F with 4J to find the solution for J: 

4J + J ≥ 55

5J ≥ 55

Now divide both sides by 5

5J/5 ≥ 55/5

J ≥ 11 

That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
8 0
3 years ago
5. Angie is mixing together yellow paint and blue paint to make 2 shades of green paint. She fills −4 of can A with yellow paint
trapecia [35]

Answer:

she can pour more paint in in can<u> </u><u>B</u>

Step-by-step explanation:

4 0
3 years ago
What is the square root of 460
Volgvan

Answer:

21.4476105895

Step-by-step explanation:

Using a calculator \sqrt{460\\}

8 0
2 years ago
Read 2 more answers
Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
3 years ago
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