Start with assigning each person with a variable to represent their height
Ebi: e
Jose: j
Derell: d
Asami: a
Ebi'd height was 2.5 cm greater than Jose's height
j + 2.5 = e
Jose's height was 3.1 cm greater than Derell's
d + 3.1 = j
Derell's height is 0.4 cm less than Asami's height
a - 0.4 = d
Ebi is 162.5 cm tall
e = 162.5
So, plug in 162.5 into any of the above equations were there is a variable of e
j + 2.5 = e
j + 2.5 = 162.5
Subtract 2.5 from both sides of the equation
j = 160 cm
Jose's height is 160 cm
Now, plug in 160 into any of the above equations where there is a j
d + 3.1 = j
d + 3.1 = 160
Subtract 3.1 from both sides of the equation
d = 156.9 cm
Derell's height 156.9 cm
so, plug in 156.9 into any of the above equations where there is a d
a - 0.4 = d
a - 0.4 = 156.9
Add 0.4 on both sides of the equation
a = 157.3 cm
Asami's height is 157.3 cm
The picture in the attached figure
we know that
area of rectangle=base*height
in this problem
base is 22 ft
height is 2 yd
convert yd to ft
1 yd is equal to 3 ft
2 yd--------> 2*3-----> 6 ft
area of rectangle=22*6-----> 132 ft²
the answer is132 ft²
I think it wold be b
please tell me if i wrong
<em>Greetings from Brasil...</em>
First degree equation. The variables are in the 1st member and the numbers in the 2nd member.
X + 6 - 2X = X - 24
X - 2X - X = - 24 - 6
- 2X = - 30
<h2>X = 15</h2>
X = tuna, y = BLT
x + y = 30
6x + 9y = 240
3y = 60
y = 20
x = 10
20 BLTs for $2.50, 10 tuna for $1.50