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choli [55]
3 years ago
12

HELP ME THIS IS DUE RN. ILL give 50 points and brainiest.

Mathematics
2 answers:
Setler [38]3 years ago
7 0

Answer:

y=1x+1

Step-by-step explanation:

it keeps going up one everytime

1x - 14y

2x - 15y

3x - 16y

4x - 17y

5x - 18y

6x - 19y

7x - 20y

8x - 21y

And so on

Maru [420]3 years ago
3 0

Answer:

y = 8x + 21

Step-by-step explanation:

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After MM students took a test, there was a total of 64% of correct answers. If the test contains 50 questions, what is the least
Blizzard [7]

Answer:

3 Questions

Step-by-step explanation:

After MM students took a test, there was a total of 64% of correct answers.

The tests contained a total of 50 questions.

Number of questions gotten to score 64%= 64% X 50 = 32 questions

If the next student wants to score 70%, he has to score

70% of the total score = 70% X 50 = 35

Therefore the least number of question more the student has to get right

=35-32

= 3 questions

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3 years ago
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What is the value of x?<br> a. 68°<br> b. 62°<br> c. 112°<br> d. 124°
Dmitrij [34]
68 degrees because 56×2=112 then 180-112=68
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3 years ago
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kifflom [539]
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7 0
3 years ago
Which equation reprints the slope intercept form of the line below ? Y- intercept = (0,2) slope = -3/7
Ann [662]

Answer:

y = -\frac{3}{7} x + 2

Step-by-step explanation:

The y-intercept of the line is (0,2)

The slope of the line is  -\frac{3}{7}

We derive the slope of a line by dividing the change in y by the change in x

So,

\frac{y - 2}{x - 0} =  -\frac{3}{7}

y - 2 =  -\frac{3}{7} x

The equation of the line therefore is;

y =  -\frac{3}{7} x + 2

5 0
3 years ago
The largest set of x values satisfying
velikii [3]

Answer:

If p\ge -\dfrac{1}{3}, then x>\dfrac{2}{3}+p and mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p

Step-by-step explanation:

Solve two inequalities for x.

1. 2,018x-p

Separate terms with x and without x into two sides:

2,018x-2,020x

Multiply by -1:

2x>-2p\\ \\x>-p

2. 7x+3p

Separate terms with x and without x into two sides:

7x-10x

Multiply by -1:

3x>2+3p\\ \\x>\dfrac{2}{3}+p

Find the largest set of x values satisfying both inequalities:

x>-p\\ \\x>\dfrac{2}{3}+p

If

-p>\dfrac{2}{3}+p\\ \\-2p>\dfrac{2}{3}\\ \\2p

then x>-p and mn=-p=p\cdot (-1),\ m+n=p-1. In this case both m and n are negative.

If p>-\dfrac{1}{3}, then x>\dfrac{2}{3}+p and mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p

If p=-\dfrac{1}{3}, then x>\dfrac{1}{3} and mn=\dfrac{1}{3}=\dfrac{1}{3}\cdot 1,\ \ m+n=\dfrac{4}{3}

7 0
3 years ago
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