Question

Solve for x n(17+x)=34x−r

Answer 1

Answer:

$x=\frac{r+17n}{34-n}$.

Step-by-step explanation:

We have been given an equation $n(17+x)=34x-r$. We are asked to solve for x.

Using distributive property, we will get:

$17n+xn=34x-r$

Now, we will subtract 34x from both sides of our equation.

$17n+xn-34x=34x-34x-r$

$17n+xn-34x=-r$

Let us subtract 17n from both sides of our equation.

$17n-17n+xn-34x=-r-17n$

$xn-34x=-r-17n$

Now we will factor out x from left side of our equation.

$x(n-34)=-r-17n$

Upon dividing both sides of our equation by $(n-34)$, we will get:

$\frac{x(n-34)}{(n-34)}=\frac{-r-17n}{(n-34)}$

$x=\frac{-r-17n}{(n-34)}$

Now we will factor out negative sign as shown:

$x=\frac{-(r+17n)}{-(-n+34)}$

$x=\frac{r+17n}{34-n}$

Therefore, the value of x is $x=\frac{r+17n}{34-n}$.

Answer 2

Answer:

$\frac{17n+r}{34-n}=x$

Step-by-step explanation:

Given :$n(17+x)=34x−r$

To Find : Find the value of x

Solution :

$n(17+x)=34x−r$

$17n+xn=34x−r$

$17n+r=34x−xn$

$17n+r=x(34−n)$

$\frac{17n+r}{34-n}=x$

Hence the value of x is $\frac{17n+r}{34-n}$