<span>An efect could be that sence the air us blowing on the hot tea that Nya has, an efect could be the temperatures mixing and the tea cooling down enough for Nya to drink</span>
Answer:
A. 1.71 m
B. 2.66 m
Explanation:
A. Determination of the height of the pier.
We'll begin by calculating the time taken for the ball to get to the water
This can be obtained as follow:
Horizontal velocity (u) = 1.27 m/s,
Horizontal distance (s) = 0.75 m
Time (t) =?
s = ut
0.75 = 1.27 × t
Divide both side by 1.27
t = 0.75 / 1.27
t = 0.59 s
Finally, we shall determine the height of the pier as follow:
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 0.59 s
Height of pier (h) =?
h = ½gt²
h = ½ × 9.8 × 0.59²
h = 4.9 × 0.3481
h = 1.71 m
Thus, the height of the pier is 1.71 m
B. Determination of the horizontal distance.
Horizontal velocity (u) = 4.50 m/s
Time (t) = 0.59 s
Horizontal distance (s) =?
s = ut
s = 4.5 × 0.59
s = 2.66 m
Thus, if the ball moved at a velocity of 4.50 m/s off the pier, it will land at a distance of 2.66 m from the end of the pier.
Answer:
Charge on Moon and Earth is 5.43x10¹³ C .
Explanation:
Gravitational force is the force of attraction between any two bodies having mass while Electrostatic force is the force experienced by two charge bodies. Electrostatic force can be attractive or repulsive.
Let M and m be the mass of Earth and Moon respectively, d is the distance between Earth and Moon and q be the charge on Earth and -q be on the Moon.
Gravitational force, F₁ =
Here G is gravitational constant.
Electrostatic force, F₂ =
Here k is Coulomb constant.
According to the problem, the gravitational force between Earth and Moon is equal to the electrostatic force between them.
F₁ = F₂
=
=
Put 6.07x10⁻¹¹ N m²/kg² for G, 5.97x10²⁴ kg for M, 7.34x10²² kg for m and 9x10⁹ N m²/C² in the above equation.
= q²
q =
q = 5.43x10¹³ C
Answer:
B) A planet's speed as it moves around the sun will not be the same in six months.
Explanation:
A planet's speed as it moves around the sun will not be the same in six months, is a statement that CANNOT be supported by Kepler's laws of planetary motion.
The answer is C, light cant pass through an opaque object