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Montano1993 [528]
3 years ago
11

You're having a hard time pushing a refrigerator across the kitchen floor. The force of your own push is 993 N. The force of fri

ction opposing your own push is 973 N. If the refrigerator has a mass of 355 kg, what is the refrigerator's acceleration
Physics
1 answer:
Helen [10]3 years ago
6 0

Answer:

The acceleration of the refrigerator is a= 0.056 ms^{-2}

Explanation:

The expression of the equation of the net force acting on the refrigerator is as follows;

F-f= ma

Here, F is the applied force, f is the force of friction, m is the mass and a is the acceleration.

It is given in the problem that you're having a hard time pushing a refrigerator having mass 355 kg across the kitchen floor. The force of your own push is 993 N. The force of friction opposing your own push is 973 N.

Put F= 993, f= 973 N and m = 355 kg in the above expression of the equation to calculate the acceleration of the refrigerator.

993 - 973 = (355)a

20 = 355 a

a= 0.056 ms^{-2}

Therefore, the acceleration of the refrigerator is a= 0.056 ms^{-2}.

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parallel circuit

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voltage will be same for both light bulbs and current will be different.

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balanced diet

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Juan and Kuri are on a carousel. Juan is closer to the center of the carousel than Kuri. Which statement describes their tangent
Licemer1 [7]

Answer:

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

Explanation:

Since Juan is closer to the center and Kuri is away from the center so we can say that Juan will move smaller distance in one complete revolution

As we know that the distance moved in one revolution is given as

d = 2\pi r

also the time period of revolution for both will remain same as they move with the time period of carousel

Now we can say that the speed is given as

v = \frac{2\pi r}{T}

so Juan will have less tangential speed. so correct answer will be

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

6 0
3 years ago
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A rod (length = 2.0 m) is uniformly charged and has a total charge of 5.0 nC. What is the electric potential (relative to zero a
Ksenya-84 [330]

Answer:

The electric potential is  V  =  15.6 V

Explanation:

From the question we are told that

   The length  of the rod is  L =  2.0 \ m

     The total charge of the rod is  q =5.0 nC = 5.0*10^{-9} C

      The length from the center is  d =  3.0 \ m

The diagram illustrating the setup for this question is shown on the first uploaded image

From the diagram the potential at point  A  dl is mathematically represented as

         dV  =  K  \frac{dq}{l}

Where K is the coulomb constant with a value  K  = 9*10^9 \   Nm^2 /C^2

where q is the charge in charge  the rod relative to its distance from A  is mathematically represented as

         dq =  \frac{q}{L}  dl

This a small unit length of the rod

So         V = \frac{q}{L}  \int\limits^4_2  {\frac{dl}{l} } \,

        =>   V =  k\frac{q}{L}  ln [\frac{4}{2} ]

              V =  k\frac{q}{L}  ln2

Substituting values

                V  =  9* 10^9  *  \frac{5*10^{-9}}{2} * ln 2

                 V  =  15.6 V

         

7 0
4 years ago
Suppose a 0.04-kg car traveling at 2.00 m/s can barely break an egg. What is the min
Paha777 [63]

Answer: The correct answer is option (A).

Explanation:

Momentum of the car with 0.04 kg mass , which travelling with velocity of 2.00 m/s

P_1=mass\times velocity=m_1\times v_1=0.04 kg\times 2.00 m/s=8.00 kg m/s

Then the maximum speed of the another car in order to not to break the eggs will be same as first car:

P_1=P_2

0.08 kg m/s=m_2\times v_2=0.08 kg\times v_2

v_2=1 m/s

Speed slightly more than 1 m/s will increase the momentum of second car and the eggs will break. So, from the given options the minimum speed need by the second car will be 1.42m/s.

4 0
4 years ago
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