I believe this is what you have to do:
The force between a mass M and a point mass m is represented by
So lets compare it to the original force before it doubles, it would just be the exact formula so lets call that F₁
So F₁ = G(Mm/r^2)
Now the distance has doubled so lets account for this in F₂:
F₂ = G(Mm/(2r)^2)
Now square the 2 that gives you four and we can pull that out in front to give
F₂ = 
G(Mm/r^2)
Now we can replace G(Mm/r^2) with F₁ as that is the value of the force before alterations
now we see that:
F₂ = F₁
So the second force will be 0.25 (1/4) x 1600 or 400 N.
Answer:
Explanation:
The horizontal distance covered by the ball in the falling is only determined by its horizontal motion - in fact, it is given by
where
is the horizontal velocity
t is the time of flight
The time of flight, instead, is only determined by the vertical motion of the ball: however, in this problem the vertical velocity is not changed (it is zero in both cases), so the time of flight remains the same.
In the first situation, the horizontal distance covered is
in the second case, the horizontal velocity is increased to
And so the new distance travelled will be
So, the distance increases linearly with the horizontal velocity.
Answer:
The Most Famous Astronomers of All Time. Karl Tate, SPACE.com. ...
Claudius Ptolemy. Bartolomeu Velho, Public Domain. ...
Nicolaus Copernicus. Public Domain. ...
Johannes Kepler. NASA Goddard Space Flight Center Sun-Earth Day. ...
Galileo Galilei. NASA
Answer:
We will use Potential Energy Formula
Potential Energy = mass × gravitation × height
PE = 0,55 × 10 × 4
PE = 22 J (A)
