Since 4pi/3 = 3pi/3 + pi/3 = pi + pi/3, that means it goes past the angle of pi (the negative x-axis), and an additional pi/3 radians. So this gives you a diagonal line that passes through the origin, from the third quadrant through to the first quadrant, and makes an angle of 60 degrees with the negative x-axis.
Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
Answer:
The answer is b because you are taking away from susan
Step-by-step explanation:
Answer:
Differential equation

Solution

Value of constant k=0.327 days^(-1)
The rumor reaches 80% at 8.48 days.
Step-by-step explanation:
We know
y(t): proportion of people that heard the rumor
y'(t)=ky(1-y), rate of spread of the rumor
Differential equation

Solving the differential equation

Initial conditions:

Value of constant k=0.327 days^(-1)
At what time the rumor reaches 80%?

The rumor reaches 80% at 8.48 days.