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hjlf
3 years ago
14

NEED HELP QUICK**

Mathematics
2 answers:
Anastasy [175]3 years ago
8 0
Answer is 3) 0.009, 0.07, 0.1, 0.106, 0.12
xxTIMURxx [149]3 years ago
6 0
Ascending means increasing. So, the only choice which increase in value during every number is 3.

<span>3) 0.009, 0.07, 0.1, 0.106, 0.12
</span>
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Cual es el 15% de 36000?
zimovet [89]
15% = 15/100 = 0,15

36000•0,15=5400
4 0
3 years ago
PLEASE HELP PLEASEEEE!!! Number 3
deff fn [24]
The equation for this is a^2+b^2=c^2 so your equation would be 7^2+20^2=X
So you square the 7 and the 20 then take the square root of X and you get
X=21.19
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6 0
3 years ago
What is the expression in radical form?<br><br> (4x3y2)310
sertanlavr [38]

Given:

Consider the given expression is

(4x^3y^2)^{\frac{3}{10}}

To find:

The radical form of given expression.

Solution:

We have,

(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

Therefore, the required radical form is \sqrt[5]{8y^3}\sqrt[10]{x^9}.

8 0
3 years ago
Which expression is equivalent to -18a^-2b^5/-12a^-4b^-6
crimeas [40]

Answer:

  c.  3a^2b^11/2

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)/(a^c) = a^(b-c)

__

 \dfrac{-18a^{-2}b^5}{-12a^{-4}b^{-6}}=\dfrac{-18}{-12}a^{-2-(-4)}b^{5-(-6)}=\boxed{\dfrac{3a^2b^{11}}{2}}

3 0
2 years ago
Please answer this correctly
olasank [31]

Answer:

12 days

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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