The <em>additional information</em> needed to prove that both triangles are congruent by the SSS Congruence Theorem would be: <em>C. HJ ≅ LN</em>
<em>Recall:</em>
- Based on the Side-Side-Side Congruence Theorem, (SSS), two triangles can be said to be congruent to each other if they have three pairs of congruent sides.
Thus, in the two triangles given, the two triangles has:
- Two pairs of congruent sides - HI ≅ ML and IJ ≅ MN
Therefore, an <em>additional information</em> needed to prove that both triangles are congruent by the SSS Congruence Theorem would be: <em>C. HJ ≅ LN</em>
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5 × x = 1/4 x = 1/4 ÷ 5 x = 1/20
Hypotenuse² = perpendicular² + base²
H² = 20²+21²
H²= 400+441 = 841
H = √841
H = 29 cm
Answer:
The solution to the box is
a = 2.1
b = 5.9
c = 0.9
d = 10
Step-by-step explanation:
To answer the equation, we simply name the boxes a,b,c and d.
Such that
a + b = 8 ---- (1)
b - c = 5 ------ (2)
d * c = 9 ------ (3)
a * d = 21 ------- (4)
Make d the subject of formula in (3)
d * c = 9 ---- Divide both sides by c
d * c/c = 9/c
d = 9/c
Substitute 9/c for d in (4)
a * d = 21
a * 9/c = 21
Multiply both sides by c
a * 9/c * c = 21 * c
a * 9 = 21 * c
9a = 21c ------ (5)
Make b the subject of formula in (1)
a + b = 8
b = 8 - a
Substitute 8 - a for b in (2)
b - c = 5
8 - a - c = 5
Collect like terms
-a - c = 5 - 8
-a - c = -3
Multiply both sides by -1
-1(-a - c) = -1 * -3
a + c = 3
Make a the subject of formula
a = 3 - c
Substitute 3 - c for a in (5)
9a = 21c becomes
9(3 - c) = 21c
Open bracket
27 - 9c = 21c
Collect like terms
27 = 21c + 9c
27 = 30c
Divide both sides by 30
27/30 = 30c/30
27/30 = c
0.9 = c
c = 0.9
Recall that a = 3 - c
So, a = 3 - 0.9
a = 2.1
From (1)
a + b = 8
2.1 + b = 8
b = 8 - 2.1
b = 5.9
From (3)
d * c = 9
Substitute 0.9 for c
d * 0.9 = 9
Divide both sides by 0.9
d * 0.9/0.9 = 9/0.9
d = 9/0.9
d = 10.
Hence, the solution to the box is
a = 2.1
b = 5.9
c = 0.9
d = 10