Find the smallest value of n such that the LCM of n and 15 is 45
2 answers:
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Answer:
is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Step-by-step explanation:
Given the function
As the highest power of the x-variable is 3 with the leading coefficients of 1.
- So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.
solving to get the zeros
∵
as
so
Using the zero factor principle
if
Therefore, the zeros of the function are:
is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.
Therefore, the last option is true.
Step-by-step explanation:
We have
First, 125 is a perfect cube because
and
x^3 is a perfect cube because
so we can use the difference of cubes identity
Let say we have two perfect cubes:
64 because 8×8×8=64
and 27 because 3×3×3=27 and let subtract
we know that
but using the difference of cubes identity we should get the same thing.
Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have
So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.
Back on to the topic,
we know that 5 is cube root of 125 and x is the cube root of x^3 so we have
Answer:
<h2>240.34</h2>Step-by-step explanation:
ΔA = 90° - 31°
= 59°
sin A = perpendicular ÷ base
sin 59° = 400 ft ÷ y
1.6643 = 400 ft ÷ y
y = 400 ÷ 1.6643
y = 240.34 ft
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