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kvasek [131]
3 years ago
5

A long distance runner starts at the beginning of a trail and runs at a rate of 6 miles per hour. Two hours later, a cyclist sta

rts at the beginning of a trail and travels at a rate of 16 miles per hour. What is the amount of time that the cyclist travels before overtaking the runner? Do not do any rounding
Mathematics
2 answers:
Leto [7]3 years ago
8 0
Well the cyclist would catch up at 48 miles because......6, 12, 18, 24, 30, 36, 48, 54, 60 and 16, 32, 48, 64, 80. Now if you find the least common factor between the two that is your answer. which is48 in this case
yanalaym [24]3 years ago
5 0
If the runner moves at 6 miles per hour for 2 hours before the cyclist starts, the runner has a 12 mile lead at the beginning. If the cyclist is going at 16 miles per hour, he is overtaking the runner at 10 miles per hour, because 16-6=10. Then, the amount of time it takes the cyclist to go 2 miles in 10 miles per hour is the answer. this is 1/5 of an hour, or 12 minutes.
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Ber [7]

Answer:

-3x + 36

it is correct answer

4 0
3 years ago
What is the inverse of y=2x squared -4
Bumek [7]
y=2x^2-4\ \ \ |+4\\\\2x^2=y+4\ \ \ |:2\\\\x^2=\dfrac{y+4}{2}\\\\x=\sqrt{\dfrac{y+4}{2}}

y^{-1}=\sqrt{\dfrac{x+4}{2}}=\dfrac{\sqrt{x+4}}{\sqrt2}=\dfrac{\sqrt{2(x+4)}}{2}=\dfrac{\sqrt{2x+8}}{2}
6 0
2 years ago
How do you write -x+3y=6 in slope intercept form?
Afina-wow [57]

Commenter jdoe said it right: solve for y and leave the rest on the other side.

-x + 3y = 6

3y = 6 + x add x on both sides

3y = x + 6 rearrange to get the x first

y = (x + 6) /3 divide both sides by 3

y = x/3 + 6/3 split the numerator (caution - never split denominators)

y = x/3 + 2 simplify 6/3


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8 0
3 years ago
Read 2 more answers
Past half hour of 6?
katrin2010 [14]
What do you mean by this ?
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4 0
3 years ago
Read 2 more answers
Quadratics need help making parabola
timama [110]

Answer:

The equation of the parabola is y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4, whose real vertex is (x,y) = (2, -5.333), not (x,y) = (2, -5).

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

(x_{1}, y_{1}) = (-2, 0), (x_{2}, y_{2}) = (6, 0), (x_{3}, y_{3}) = (0, -4)

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

4\cdot a -2\cdot b + c = 0 (1)

36\cdot a + 6\cdot b + c = 0 (2)

c = -4 (3)

The solution of this system is: a = \frac{1}{3}, b = - \frac{4}{3}, c = -4. Hence, the equation of the parabola is y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4. Lastly, we must check if (x,y) = (2, -5) belongs to the function. If we know that x = 2, then the value of y is:

y = \frac{1}{3}\cdot (2)^{2}-\frac{4}{3}\cdot (2) - 4

y = -5.333

(x,y) = (2, -5) does not belong to the function, the real point is (x,y) = (2, -5.333).

5 0
2 years ago
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