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Leya [2.2K]
2 years ago
8

SOMONE HELP ME I HAVE TO DO THIS AFTER SCHOOL PLS ASAP!!!

Mathematics
1 answer:
Scrat [10]2 years ago
3 0

Answer:

1 no

2 I don't know

3 no

4 yes

5 2.5 is the slope

6 -0.5

7 no slope

Step-by-step explanation:

1 no because the y overlaps

2 not sure

3 it over laps

4 it never overlaps

5 y=2.5x-3

6 y=-0.5x+1

7 no slope it's just x=-2

for the 5-7 you can type that into demos and get more info

y=mx+b

m is the slope and b is y intercept

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6 0
3 years ago
Find the volume of the solid under the plane 5x + 9y − z = 0 and above the region bounded by y = x and y = x4.
svp [43]
<span>For the plane, we have z = 5x + 9y

For the region, we first find its boundary curves' points of intersection.
x = x^4 ==> x = 0, 1.

Since x > x^4 for y in [0, 1],

The volume of the solid equals

\int\limits^1_0 { \int\limits_{x^4}^x {(5x+9y)} \, dy } \, dx = \int\limits^1_0 {\left[5xy+ \frac{9}{2} y^2\right]_{x^4}^{x}} \, dx  \\  \\ =\int\limits^1_0 {\left[\left(5x(x)+ \frac{9}{2} (x)^2\right)-\left(5x(x^4)+ \frac{9}{2} (x^4)^2\right)\right]} \, dx  \\  \\ =\int\limits^1_0 {\left(5x^2+ \frac{9}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx =\int\limits^1_0 {\left( \frac{19}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx \\  \\ =\left[ \frac{19}{6} x^3- \frac{5}{6} x^6- \frac{1}{2} x^9\right]^1_0

=\frac{19}{6} - \frac{5}{6} - \frac{1}{2} =\bold{ \frac{11}{6} \ cubic \ units}</span>
8 0
3 years ago
How to solve this please help!!
Angelina_Jolie [31]
Mary is incorrect. Perimeter is not proportional to area. An example which you can use is garden A is an 8 by 1 rectangle. The perimeter is 18 while the area is 8. Graden B is a 4 by 4 square. The perimeter is 16 (less than garden A) while the area is 16 (two times more than garden B). 
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2 years ago
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Hope this helped C=2 PIE R

3 0
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