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3 years ago

9

27. Stuart wants to play a trick on his friend by hiding his pencil in the box of tissues shown below. If

1 answer:

Alex17521 [72]3 years ago

5 0

Answer:

Well if it’s a regular box I’m sure it will fit, because a box of tissues is at least 10 inches long in diameter.

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What is the answer to this solution. -7r−4≥ 4r+2

tia_tia [17]

Answer:

The solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

$-7r-4\ge \:4r+2$

Add 4 to both sides

$-7r-4+4\ge \:4r+2+4$

Simplify

$-7r\ge \:4r+6$

Subtract 4r from both sides

$-7r-4r\ge \:4r+6-4r$

Simplify

$-11r\ge \:6$

Multiply both sides by -1 (reverses the inequality)

$\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)$

Simplify

$11r\le \:-6$

Divide both sides by 11

$\frac{11r}{11}\le \frac{-6}{11}$

Simplify

$r\le \:-\frac{6}{11}$

Therefore, the solution is:

$-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}$

Please check the attached line graph below.

7 0

3 years ago

A line passes through the two points (-4,6) and (2,-5). Calculate the following parts:

Viktor [21]

A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.

<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>

Its slope would be:

$m = \dfrac{y-q}{x-p}$

The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.

The slope m of the line is given as

$m = \dfrac{y-q}{x-p}\\\\ m = \dfrac{-5-6}{2+4}\\\\ m = \dfrac{-11}{6}$

The equation of a line is

$( y -y_0) = m (x - x_0)\\\\( y -6) = \dfrac{-11}{6} (x+4)\\\\6( y -6) = (-11) (x+4)\\\\6y -36 = (-11x +44)\\\\11x +6y - 80 = 0$

Hence, the equation is 11x +6y - 80 = 0

Learn more about slopes here:

brainly.com/question/2503591

#SPJ4

8 0

2 years ago

Help me pls this is math and im so confused

EleoNora [17]

9.08+x=25.08
-9.08 -9.08
x=16
3/4x=12
x4/3 x4/3
x=16

4.5x=72
/4.5 /4.5
x=16

Both

8 0

3 years ago

Answer for brainliest what is the volume

lisov135 [29]

Answer:

The answer is 36

Step-by-step explanation:

To find the volume you:

$multiply \: (6 \times 3 \times 2) = 36{cm}^{3}$

6 0

2 years ago

Read 2 more answers

In pensacola in june, high tide was at noon. the water level at high tide was 12 feet and 2 feet at low tide. assuming the next

castortr0y [4]

An equation for water level in june for pensacola as a function of time (t) is f(t) = 5 cos pi/6 t + 7.

Which equation of cos show period amplitude ?

The equation given below show aplitude and period

$y = A cos bx + c$

where A = amplitude,

b = 2 pi/Period,

Period = 12 hrs,

c = midline,

x = t and y = f(t)

We have to find the amplitude

<h3>What is the formula for the amplitude?</h3>

$A = 1/2 (Xmax - Xmin)$

$12 - 2 / 2 = 10/2 = 5$

$b = 2 pi / 12 = pi/6$

$c = 1/2 (Xmax + Xmin)$

$12+2/2 = 7$

Therefore, the an equation for water level in june for pensacola as a function of time (t)

$f(t) = 5 cos pi/6 t + 7$

To learn more about the function of time visit:

brainly.com/question/24872445

3 0

2 years ago