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RSB [31]
4 years ago
11

how long does it take an acorn to hit the ground after dropping from the branch of a tree 12.5 m high?

Physics
1 answer:
Grace [21]4 years ago
6 0
The right formula to use is: T^2= 2d/g
where T= time taken
d = 12.5m
g = is a constant and is equal to 9.8m/s
therefore, T^2 = 2*12.5/9.8 
Using the values above, the time taken for the acorn to reach the ground is 1.59 second
T = 1.59 S
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If a sample of a radioactive isotope has a half-life of 1 year, how much of the original sample will be left at the end of the s
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1/4 of the original

Explanation:

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1 year ago
A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?
AfilCa [17]
First convert 90km/hr to m/s.

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3 0
3 years ago
Rearranging the equation m= 5Kg and a= 2 m\s2
olganol [36]

The force of the object with the given mass and acceleration is determined as 10 N.

<h3>Force of the object</h3>

The force of the given object is calculated from Newton's second law of motion as follows;

F = ma

where;

  • m is mass of the object = 5 kg
  • a is acceleration of the object = 2 m/s²

F = 5 x 2 = 10 N

Thus, the force of the object with the given mass and acceleration is determined as 10 N.

The complete question is below:

Rearranging the equation m = F/a and solve for F, m= 5Kg and a= 2 m\s2

Learn more about force here: brainly.com/question/12970081

#SPJ1

6 0
2 years ago
In a region of space where gravitational forces can be neglected, a sphere is accelerated by a uniform light beam of intensity 8
BlackZzzverrR [31]

Answer:

The correct answer is B

Explanation:

To calculate the acceleration we must use Newton's second law

      F = m a

      a = F / m

To calculate the force we use the defined pressure and the radiation pressure for an absorbent surface

       P = I / c        absorbent surface

       P = F / A

       F / A = I / c

       F = I A / c

The area of ​​area of ​​a circle is

      A = π r²

We replace

     F = I π r² / c

Let's calculate

     F = 8.0 10⁻³ π (1.0 10⁻⁶)²/3 10⁸

     F = 8.375 10⁻²³ N

Density is

      ρ = m / V

      m = ρ V

      m = ρ (4/3 π r³)

      m = 4500 (4/3 π (1 10⁻⁶)³)

      m = 1,885 10⁻¹⁴ kg

Let's calculate the acceleration

     a = 8.375 10⁻²³ / 1.885 10⁻¹⁴

     a = 4.44 10⁻⁹ m/s²               absorbent surface

The correct answer is B

4 0
3 years ago
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