Energy in a machine can be something technical like a wire or something went wrong with the system
Answer:
V = 493421.05 [gal]
Explanation:
This is a problem that consists of handling units, we can calculate by first-hand the volume, then convert units from cubic meters to gallons.
V = 50 * 25 * 1.5
V = 1875 [m^3]
Now we need to convert units, using the proper conversion factor.
![1875[m^3]*\frac{1000lt}{1m^3} *\frac{1gal}{3.8lt} \\493421.05[gal]](https://tex.z-dn.net/?f=1875%5Bm%5E3%5D%2A%5Cfrac%7B1000lt%7D%7B1m%5E3%7D%20%2A%5Cfrac%7B1gal%7D%7B3.8lt%7D%20%5C%5C493421.05%5Bgal%5D)
a. 25 joules of work is done by the object.
Explanation:
According to the work-energy theorem, the work done ON an object is equal to the change in kinetic energy of the object, therefore:

where
is the final kinetic energy of the car, with
m = 2 kg being the mass of the car
v = 0 is the final speed of the car (brought to rest)
is the initial kinetic energy of the car, with
u = 5 m/s being the initial speed of the car
Substituting numbers, we find:

The negative sign means that the work done ON the car is negative: this means therefore that the work has been actually done BY the car. In fact, the car has lost its kinetic energy: this means that it has done work on the surrounding, converting its kinetic energy into other forms of energy.
Learn more about work and kinetic energy:
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Answer:
Time period, T = 403.78 years
Explanation:
It is given that,
Orbital distance, 
Mass of the Earth, 
Mass of the planet, 
Let T is the orbital period of this planet. The Kepler's third law of motion gives the relation between the orbital period and the orbital distance.



or
T = 403.78 years
So, the orbital period of this planet is 404 years. Hence, this is the required solution.
Explanation:
Given data:
Area A = 10 cm×2 cm = 20×10⁻⁴ m²
Distance d between the plates = 1 mm = 1×10⁻³m
Voltage of the battery is emf = 100 V
Resistance = 1025 ohm
Solution:
In RC circuit, the voltage between the plates is related to time t. Initially the voltage is equal to that of battery V₀ = emf = 100V. But After time t the resistance and capacitor changes it and the final voltage is V that is given by

Taking natural log on both sides,

(1)
Now we can calculate the capacitance by using the area of the plates.
C = ε₀A/d
= 
= 18×10⁻¹²F
Now we can get the time when the voltage drop from 100 to 55 V by putting the values of C, V₀, V and R in the equation (1)

= -(1025Ω)(18×10⁻¹² F) ln( 1 - 55/100)
= 15×10⁻⁹s
= 15 ns