Answer:
n = 1.4
Explanation:
Given,
R1 = 18 cm, R2 = -18 cm
From lens makers formula
1/f = (n - 1)(1/18 + 1/18) = (n-1)/9
f = 9/(n-1)
Power, P = 1/f ( in m) = (n-1)/0.09
Now, this lens is in with conjunction with a concave mirror which then can be thought of as to be in conjunction with another thin lens
Power of concave mirror = P' = 1/f ( in m) = 2/R = 2/0.18 = 1/0.09
Net power of the combination = 2P + P' = 2(n-1)/0.09 + 1/0.09 = 1/0.05
n = 1.4
Resistance reduces the current. If there is more resistance, there is less current.
Explanation:
Given that,
The optical power of the equivalent single lens is 45.4 diopters.
(a) The relationship between the focal length and the focal length is given by:


f = 0.022 m
or
f = 2.2 cm
(b) We need to find how far in front of the retina is this "equivalent lens" located. It is given by using lens formula as :

Here, u = infinity

v = 2.2 cm
So, at 2.2 cm in front of the retina is this "equivalent lens" located.
Hence, this is the required solution.