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3 years ago

Why it is not advisable for soldiers to march across the bridge in rythm

Physics

1 answer:

Musya8 [376]3 years ago

7 0

Answer:

Marching soldiers are cautioned to break stride on a bridge, lest they match the bridge's frequency of vibration. ... A force that's applied to an object at the same frequency as the object's natural frequency will amplify the vibration of the object in an occurrence called mechanical resonance.

Explanation:

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2 Calculate the mass of a car that hits a wall, during an accident, with a force of 961 N and an acceleration of 31m/s2. (4D) (F

Pachacha [2.7K]

Answer: 31kg

Explanation:

(F=mxa)

Rearranged

M=f÷a

961÷31=31

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3 years ago

Who knows the egg drop challenge

liubo4ka [24]

I know. If you're asking for ideas, I once did one and it did not break. I just took a cardboard box, filled it with thins like packing peanuts, crumpled newspaper, and put the egg inside a few layers of socks in the middle, and taped the box tightly shut. Our science teacher dropped from the roof of the school, and there wasn't even a crack on mine!

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3 years ago

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katen-ka-za [31]

Answer:

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4 years ago

Power Rating of a Resistor. The power rating of a resistor is the maximum power the resistor can safely dissipate without too gr

IgorLugansk [536]

(a) 273.9 V

The power rating of the resistor is given by

$P=\frac{V^2}{R}$

where

P is the power rating

V is the potential difference across the resistor

R is the resistance

If the maximum power rating is $P=5.0 W$ , and the resistance of the resistor is $R=15 k\Omega = 15000 \Omega$ , then we can find the maximum potential difference across the resistor by re-arranging the previous equation for V:

$V=\sqrt{PR}=\sqrt{(5.0 W)(15000 \Omega)}=273.9 V$

(b) 1.6 W

In this case, we have:

$R=9.0 k\Omega = 9000 \Omega$ is the resistance of the resistor

$V=120 V$ is the potential difference across the resistor

So we can find the power rating by using the same formula of part (a):

$P=\frac{V^2}{R}=\frac{(120 V)^2}{9000 \Omega}=1.6 W$

(c) Maximum voltage: 14.1 V; Rate of heat: 2.00 W and 3.00 W

Here we have two resistors of

$R_1 = 100 \Omega\\R_2 = 150 \Omega$

and each resistor has a power rating of

P = 2.00 W

So the greatest potential difference allowed in the first resistor is

$V=\sqrt{PR_1}=\sqrt{(2.00 W)(100 \Omega)}=14.1 V$

While the greatest potential difference allowed in the second resistor is

$V=\sqrt{PR_2}=\sqrt{(2.00 W)(150 \Omega)}=17.3 V$

So the greatest potential difference allowed not to overheat either of the resistor is 14.1 V.

In this condition, the power dissipated on the first resistor is 2.00 W, while the power dissipated on the second resistor is

$P_2 = \frac{V^2}{R_2}=\frac{(14.1 V)^2}{150 \Omega}=1.33 W$

And this corresponds to the rate of heat generated in the first resistor (2.00 W) and in the second resistor (1.33 W).

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3 years ago

What type of eclipse is shown? How do you know?

Sonja [21]

That is a lunar eclipse. At night, when the Earth is between the Sun and the moon, the moon would appear to be red. Just for future reference, a solar eclipse is when the Moon is between the Sun and Earth. Speaking of which, check out the solar eclipse this August!

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3 years ago

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Why it is not advisable for soldiers to march across the bridge in rythm​

Why it is not advisable for soldiers to march across the bridge in rythm