Answer:
V = I(R+r)
Explanation:
According to ohms law, the current (I) passing through a metallic conductor at constant temperature is directly proportional to the potential difference (V) across its end.
Mathematically, V= IR where V is the potential difference
I is the current
R is resistance
Given emf (E) = IRt... (1)
where E is the emf
Rt is the total equivalent resistance
The external resistance Rv is connected in series with the internal resistance 'r' to give total equivalent resistance Rt = (R+r)
Substituting in equation 1
E = I(R+r)
The equivalent potential difference V = I(R+r)
Answer:
lift
weight
thrust
air resistance
Explanation:
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Answer:
e^-4t e^-5t
Explanation:
solving s²+9s+20 quadratically we have (s+4)(s+5)
x(s) can be written as x(s) =(1/s+4)(1/s+5)
if we take the laplace inversve
L-¹ (s)=L-1(1/s+4) L-1(1/s+5)
we have e^-4t e^-5t
Answer:
Work done in all the three cases will be the same.
Explanation:
1) The free falling body has only one force acting on it, the gravitational force. The work done on the body = mgH (Gravitational potential energy)
2) There are two forces acting on the body going down on a frictionless inclined plane - gravity and the normal force. The gravitational potential energy will be the same. The work done due to the normal force is zero, since the direction of the force is perpendicular to the displacement. Hence, total work done on the body = mgH
3) In the case of the body swinging on the end of a string, the change in gravitational potential enrgy will once again be the same since difference in height is H. The additional force on the body is the tension due to the string. But the work done due to this force is <em>zero, </em>since the displacement of the body is perpendicular to the tension. Therefore, the total work done on the body is once again mgH.
