The friction between the tires and the road causes loss of energy in the form of heat-energy.
<h3>What is kinetic energy?</h3>
The term kinetic energy refers to the energy of an object that is in motion. The pasengers that are sitting at a point possess potential energy. If the bus stops suddenly, the potential energy of the passengers is converted to kinetic energy as they move forward.
Since friction causes loss of energy, the friction between the tires and the road causes looss of energy in the form of heat-energy.
Learn more about kinetic energy: brainly.com/question/12669551
Answer:
Consider the followig calculation
Explanation:
a) use deal equation:
PV = nRT
ρ = m/V,= ==> V = m/ρ
therefore,
ρ = Pm/RT
convert 95 oF in degree
95 oF = 308.15 K
1 atm = 1.013 * 105 pascal
ρ = 1.013*105 * 29 * /8.314 * 308.15
= 1.146 kg/m3
b) again use ideal gas equation:
ρ = Pm/RT
T = 50 oF = 283.15 K
1 atm = 1.013 * 105 pascal
molar mass will be same
ρ = 1.013 * 105 * 29 / 8.314 * 283.15
ρ = 1.248 kg / m3
So,
c) . more than density of the hot, dry air computed in part (a)
The right answer for the question that is being asked and shown above is that: "C. <span>. The properties change going across each row. " the </span>statement that applies to the horizontal rows or periods in the periodic table is that t<span>he properties change going across each row. </span>
Answer:
Discuss Your Presentation With an Expert
1) Skip the Stock Template.
2) Don't Use More than 6 Lines of Text.
3) Ditch the Bullet Points.
4) Use Sans Serif Fonts.
5) Size Fonts Appropriately.
6) Maintain a Strong Contrast Between Text and Background.
7) Use No More than 5 Colors.
8) Use Contrasting Text Colors to Draw Attention.
Answer : The temperature of the hot reservoir (in Kelvins) is 1128.18 K
Explanation :
Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.
Formula used for efficiency of the heat engine.
where,
= efficiency = 0.780
= Temperature of hot reservoir = ?
= Temperature of cold reservoir = 
Now put all the given values in the above expression, we get:
Therefore, the temperature of the hot reservoir (in Kelvins) is 1128.18 K
