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Blizzard [7]
3 years ago
15

The velocity v of blood that flows in a blood vessel with radius r and length ℓ at a distance r from the central axis is v(r) =

p 4ηℓ (r2 − r2) where p is the pressure difference between the ends of the vessel and η is the viscosity of the blood. find the average velocity vave (with respect to r) over the interval 0 ≤ r ≤ r. (use eta for η. use capital p for pressure.)
Mathematics
1 answer:
pogonyaev3 years ago
7 0
v(r)=4P\eta\ell(R^2-r^2)

(assuming R is the radius of the vessel, and that 0\le r\le R)

The average velocity of the blood is given by

\displaystyle\frac1{R-0}\int_{r=0}^{r=R}v(r)\,\mathrm dr
=\displaystyle\frac{4P\eta\ell}R\int_{r=0}^{r=R}(R^2-r^2)\,\mathrm dr
=\dfrac{4P\eta\ell}R\left(\dfrac23R^3\right)
=\dfrac{8P\eta\ell}3R^2
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WILL GIVE BRAINLIEST. Tickets to a show cost $3 for students and $7 for adults. If 250 tickets were sold and ticket sales totale
Diano4ka-milaya [45]

Answer:

88 adult tickets were sold

Step-by-step explanation:

3s + 7a = 1102

(s + a = 250)-3

   3s + 7a = 1102

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4a = 352                  Divide both sides by 4

a = 88

Now plug this into the second equation

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s = 162

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7 0
2 years ago
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Write each of the following expressions as a powers of 2: (4·25)÷(23· 1/16 )
WITCHER [35]
<span>(4 · 2^5) ÷ (2^3 · 1/16 )

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6 0
2 years ago
Two corresponding sides of similar triangles are 2 cm and 5 cm. What is the area of the second triangle if the area of the first
Stella [2.4K]

Answer:

(1) Area of second triangle= 50 cm^2.

(2) Area of ΔABC=98 cm^2.

   and Area of ΔDFG=175 cm^2.

Step-by-step explanation:

<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>

i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

\dfrac{a^2}{b^2}=\dfrac{A}{B}

(1)

for the first question:

we have a=2, b=5.

A=8 cm^2.

Hence,

\dfrac{2^2}{5^2}=\dfrac{8}{B}\\\\\dfrac{4}{25}=\dfrac{8}{B}

B=50 cm^2.

Hence, the area of second triangle is 50 cm^2.

(2)

In second option we have:

a=6 and b=5.

A-B=77 cm^2.

A=77+B

\dfrac{6^2}{5^2}=\dfrac{A}{B}\\  \\\dfrac{36}{25}=\dfrac{77+B}{B}\\  \\36B=25\times77+25B\\\\36B-25B=25\times77\\\\11B=25\times77\\\\B=25\times7\\\\B=175

Hence area of second triangle i.e. ΔDFG is 175 cm^2.

and area of first triangle i.e. ΔABC=175-77=98 cm^2.




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