Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then
( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165
For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35
Answer:
The required expression is f = 3+6t
Step-by-step explanation:
Let t represent number of tens
Let f represent number of fives
So, the expression for number of fives can be formed by using:
The number of fives is 3 more than six times the number of tens.
f = 3+6t
So, the required expression is f = 3+6t
Answer:
The sum of the first 6 terms is 3,412.5.
Step-by-step explanation:
The second term of the geometric series is given by:
Where a1 is the first term and r is the common ratio. The seventh term can be written as a function of the second term as follows:
![a_{7}=a_{1}*r^{6} \\a_{7}=a_{2}*r^{5} \\10,240 = 10*r^{5}\\r=\sqrt[5]{1024} \\r = 4](https://tex.z-dn.net/?f=a_%7B7%7D%3Da_%7B1%7D%2Ar%5E%7B6%7D%20%5C%5Ca_%7B7%7D%3Da_%7B2%7D%2Ar%5E%7B5%7D%20%5C%5C10%2C240%20%3D%2010%2Ar%5E%7B5%7D%5C%5Cr%3D%5Csqrt%5B5%5D%7B1024%7D%20%5C%5Cr%20%3D%204)
The sum of "n" terms of a geometric series is given by:
The sum of the first 6 terms is 3,412.5.
Answer:
Yep, looks like a legit problem to me
Step-by-step explanation:
