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lozanna [386]
4 years ago
15

An angle's initial ray points in the 3-o'clock direction and its terminal ray rotates CCW. Let θ represent the angle's varying m

easure (in radians).
If θ=0.5θ=0.5 what is the slope of the terminal ray?
If θ=1.78θ=1.78, what is the slope of the terminal ray?

Write an expression (in terms of θθ) that represents the varying slope of the terminal ray.
Mathematics
1 answer:
Alexxandr [17]4 years ago
7 0

Answer:

0.546 , -4.71

Step-by-step explanation:

Given:

An angle's initial ray points in the 3-o'clock direction and its terminal ray rotates counter -clock wise.

Here, Slope = tan\theta

If θ = 0.5

Then, Slope = tan(θ) = tan(0.5) = 0.546

If θ = 1.78

Then, Slope = tan(θ) = tan(1.78) = - 4.71

The expression (in terms of θ) that represents the varying slope of the terminal ray.

Slope = m = tanθ, where θ is the varying angle

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Hello! For this question, you solve using order of operations, which you probably already have remembered as PEMDAS. Anytime a number is raised to the 0 power, that is equivalent to 1. 0.5^0 is 1. 250 * 1 is 250. x = 0 gives us the answer of 250. Now, let's solve for the number by the second power. 0.5² is 0.25. 250 * 0.25 is 62.5. x² gives us 62.5. Now, let's subtract the two numbers together. 250 - 62.5 is 187.5. Because the number is decreasing, the slope is negative, so the answer is -187.5. Your answer is correct.
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