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torisob [31]
2 years ago
6

What are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2 x = ±6 x = ±5 no real solution btw i just clicked the las

t choice on accident

Mathematics
2 answers:
OLEGan [10]2 years ago
4 0

Answer:

Option C

Step-by-step explanation:

we need to find the solution(s) to the quadratic equation 50 – x^2 = 0

50 – x^2 = 0

Subtract 50 from both sides

– x^2 = -50

Now divide by -1 from both sides

x^2 = 50

To remove square , take square root on both sides

x=+-\sqrt{50}

x=+-\sqrt{25*2}

x=+-5\sqrt{2}

Option C is the answer

bagirrra123 [75]2 years ago
3 0
50-x^2=0
Move the x^2 to the other side
x^2=50
Now take the square root of both sides
x=+_(50)^1/2 (^1/2 means square root)(+_ is plus or minus. Sorry XD)
Now simplify the square root
X=+_5(2)^1/2
Voila. The answer is C
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vagabundo [1.1K]

Answer:

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Step-by-step explanation:

g(x) = x³ − 4x² − x + 22

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We know -2 is a root.  The other two roots are irrational.  To find them, we must find the other factor of g(x).  We can do this using long division, or we can factor using grouping.

g(x) = x³ − 4x² − 12x + 11x + 22

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g(x) = x (x − 6) (x + 2) + 11 (x + 2)

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