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antiseptic1488 [7]
3 years ago
11

Calculate the weight in grams of the primary standard solid oxalic acid needed to prepare 250 ml of a 0.200 n solution to be use

d in this laboratory exercise.
Chemistry
1 answer:
slamgirl [31]3 years ago
3 0

Answer:

2.25 g.

Explanation:

  • Firstly, we can define the noramlity as <em>the number of gram equivalents of the solute in 1.0 L of the solution.</em>

<em>N = (mass / equivalent mass) of the solute x (1000 / V of the solution)</em>

The solute is oxalic acid.

N is the normality of the solution <em>(N = 0.2 N)</em>,

mass of the solute (oxalic acid) (??? needed to be calculated),

equivalent mass of the oxalic acid = molar mass / n (the no. of reproducible H) = (90.03 g/mol) / (2) = 45.015.

V is the volume of the solution (V = 250 ml).

∴ The mass of the oxalic acid in g = (N x equivalent mass x V) / 1000 = (0.2 N) (45.015) (250.0 ml) / 1000 = 2.25 g.

<u><em>Very important note:</em></u>

If the solute source is oxalic acid dihydrate:

The molar mass = 126.07 g/mol.

The equivalent mass = 63.035 g.equ./mol.

∴ The mass of the oxalic acid in g = (N x equivalent mass x V) / 1000 = (0.2 N) (63.035) (250.0 ml) / 1000 = 3.15 g.

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Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

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