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3 years ago

What is the correct answer to the following equation? Include a Step-by-Step process.

Mathematics

1 answer:

vivado [14]3 years ago

6 0

The correct answer is 41 1/4. I have included a photo of my work.

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Pls answer i'll mark u brainlist

In-s [12.5K]

Answer: 2/3 hours

Step-by-step explanation:

okay so the speed now is 850, which is 850/340 = 2.5 times the original speed

Since It's 2.5 times the original speed,

2.5x = 5/3

so x = 5/3/2.5 = 2/3

7 0

3 years ago

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Todd begins piano practice ar 4:15 p.m. and ends at 5:50 p.m. How long does he practice

kumpel [21]

He practiced for 1 hour and 30 minutes

4 0

3 years ago

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8 times the sum of a number and 5

kherson [118]

The equation is 8(n+5)

4 0

3 years ago

Evaluate the function for f (2) = x^3 - 2 A.4 B.6 C.8 D.10

ElenaW [278]

Answer:

A. 4

Step-by-step explanation:

Hope this helps!

5 0

3 years ago

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Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

Surface is given by g(x) = $16x^{2} + 4y^{2} - 3$

Therefore, tex]\hat{N} = grad(g(x))[/tex]

$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\x^{2}&4x&z^{2}\end{array}\right]$

Curl f(x) = (0,0,4)

Putting all values in Stokes Theorem,

$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

$I= \int \int\limits {(0,0,4)\cdot(32x,8y,0)} \, dx$

I=0

Thus, The circulation of the field f(x) over curve C is Zero

3 0

3 years ago