<span>a. 3.1 calories in heat were released by the burning candy bar sample
b. The energy value of the sample was 3.1 Cal/g
c.The total caloric content of the candy bar is 232.5 Calories, derived by multiplying the total mass of the candy bar by its fuel value per gram</span>
Atomic number, because the atomic number is unque to each individua element.
No. of atoms=mols*avagadros no.
N=n*No
N=17 * 6.022 *10^23
No. Of atoms=(17) (6.022*10^23)
