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hichkok12 [17]
3 years ago
15

A 15.6 grams of ethanol absorb 868 J as it is heated. The initial temperature is 21.5 degrees Celsius. What is the final tempera

ture if the specific heat of ethanol is 2.41 Joules/ grams Celsius?
Chemistry
1 answer:
77julia77 [94]3 years ago
3 0
You have to use the equation q=mcΔT and solve for T(final).  
T(final)=(q/mc)+T(initial)
q=the amount of energy absorbed or released (in this case 868J)
m=the mass of the sample (in this case 15.6g)
c= the specific heat capacity of the substance (in this case 2.41 J/g°C)
T(initial)=the initial temperature of the sample (in this case 21.5°C)

When you plug everything in, you should get 44.6°C.
Therefore the final temperature of ethanol is 44.6°C

I hope this helps.  Let me know if anything is unclear.
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The given reaction is a combustion reaction of benzene,

C

6

H

6

. From its balanced chemical equation,

2

C

6

H

6

+

15

O

2

→

12

C

O

2

+

6

H

2

O

,

the mass of carbon dioxide

(

C

O

2

)

produced from 20 grams (g) of

C

6

H

6

is determined through the molar mass of the two compounds, given by,

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2

=

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/

m

o

l

M

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H

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=

78.11

g

/

m

o

l

and their mole ratio:

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m

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2

m

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→

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o

l

C

O

2

1

m

o

l

C

6

H

6

With this,

m

a

s

s

o

f

C

O

2

=

(

20

g

C

6

H

6

)

(

1

m

o

l

C

6

H

6

78.11

g

C

6

H

6

)

(

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

)

(

44.01

g

C

O

2

1

m

o

l

C

O

2

)

=

(

20

)

(

6

)

(

44.01

)

g

C

O

2

78.11

=

5281.2

g

C

O

2

78.11

m

a

s

s

o

f

C

O

2

=

67.6

g

C

O

2

Therefore, the mass in grams of

C

O

2

formed from 20 grams of

C

6

H

6

is

67.6

g

C

O

2

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