Answer:
In a homogeneous mixture, there is uniform distribution of particles.
What volume (in L) of a 1.25 M
1 answer:
Answer:
V1= 0.305L
Explanation:
To find the initial volume of 1.25M potassium fluoride needed to make tge dilution specified in the question, we can use: C1 × V1 = C2 × V2
Since the question wants the volume in litres, convert 455 mL to L
455/ 1000
= 0.455 L
Now make the substitution
1.25 × V1 = 0.838 × 0.455
Rearrange to make V1 the subject
V1=
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The question is incomplete, here is the complete question:
Suppose the reaction is:
If 6 moles of A and 2 moles of B are reacted, what is the maximum number of moles of C that can be formed
<u>Answer:</u> The maximum amount of C produced will be 1 mole
<u>Explanation:</u>
We are given:
Moles of A = 6 moles
Moles of B = 2 moles
For the given chemical reaction:
By Stoichiometry of the reaction:
2 moles of B reacts with 1 mole of A
So, 2 moles of B will react with = mole of A
As, As, given amount of A is more than the required amount. So, it is considered as an excess reagent.
Thus, B is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of B produces 1 mole of C
So, 2 moles of given B will produce of C
Hence, the maximum amount of C produced will be 1 mole