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soldi70 [24.7K]
3 years ago
15

What volume (in L) of a 1.25 M

Chemistry
1 answer:
sleet_krkn [62]3 years ago
4 0

Answer:

V1= 0.305L

Explanation:

To find the initial volume of 1.25M potassium fluoride needed to make tge dilution specified in the question, we can use: C1 × V1 = C2 × V2

Since the question wants the volume in litres, convert 455 mL to L

455/ 1000

= 0.455 L

Now make the substitution

1.25 × V1 = 0.838 × 0.455

Rearrange to make V1 the subject

V1=

\frac{0.838 \times 0.455}{1.25 }  = 0.305

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