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lesantik [10]
3 years ago
11

If the side ratio is 9:12, then the volume ratio is

Mathematics
1 answer:
Reika [66]3 years ago
5 0
I think it’s D because the ratio
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Diameter of a circle is two units. What is the radius of the circle?
bonufazy [111]
Answer is 3.5 feet enjoy
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3 years ago
HOW DO I SOLVE THIS PLEASE HELP
malfutka [58]

Answer:

  x = 15

Step-by-step explanation:

We assume you want to find the value of x.

Know (or prove) that in this geometry, all of the right triangles are similar. That means the ratios of corresponding sides are proportional.

  short side / hypotenuse = 9/x = x/25

  x^2 = (9)(25) . . . . . . . . . . multiply by 25x ("cross multiply")

  x = √((9)(25)) = (3)(5) . . . take the square root

  x = 15

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2 years ago
What is .13 repeating as a fraction?
Irina18 [472]
13/99 is the fraction.
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3 years ago
What is the value of x in the equation 1.5(x + 4) - 3=4.5(x-2)
anyanavicka [17]
Hi there!

The Eqn. is :-

1.5 (x + 4) - 3 = 4.5 (x - 2)

1.5x + 6 - 3 = 4.5x - 9

Combining the like terms :-

1.5x - 4.5x = - 9 - 6 + 3

- 3x = - 15 + 3

- 3x = - 12

x = \dfrac {- 12}{- 3}

x = 4

Hence, the required answer is → x = 4

~ Hope it helps!
8 0
3 years ago
Read 2 more answers
Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon
Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

<u>p | q | p→q </u>

T | T |   T    

T | F |   F    

F | T |   T    

F | F |   T    

(a) and (b) can be seen from truth tables:

for (a) <u>p∧q</u>:

<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>

T | T |  F  |   F     |    T       |  T

T | F |  T  |  T      |    F       |  F

F | T |  F  |  T      |    F       |  F

F | F |  T  |  T      |    F       |  F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

<u>p | q | ¬p | ¬p→q | p∨q</u>

T | T |  F  |   T     |    T    

T | F |  F  |   T     |    T    

F | T |  T  |   T     |    T    

F | F |  T  |   F     |    F    

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0
3 years ago
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