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3 years ago

9. Find the point from Y to X that is 3/4 of YX.

Mathematics

2 answers:

masha68 [24]3 years ago

5 0

Uhhh what are the coordinates of points X and Y? Please write in the comments so that I can help you.

monitta3 years ago

5 0

Answer:

(2,-4)

Step-by-step explanation:

Use a variation of the midpoint formula : x = 1/4x1+3/4x2.

Also use this formula for the y coordinates as well.

For the x coordinate, you should get -5/2+9/2 which is 2.

For the y coordinate, you should get -1/4-15/4 which is -4.

Hope this helps.

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Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

$\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6$

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

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3 years ago

I need help with number 7.

NeX [460]

what the number.

yaar

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3 years ago

Read 2 more answers

Four teams A,B,C, and D compete in a tournament, and exactly one of them will win the tournament. Teams A and B have the same ch

beks73 [17]

Answer:

A= 0,2

B= 0,2

C= 0,4

D=0,2

Step-by-step explanation:

We know that only one team can win, so the sum of each probability of wining is one

P(A)+P(B)+P(C)+P(D)=1

then we Know that the probability of Team A and B are the same, so

P(A)=P(B)

And that the the probability that either team A or team C wins the tournament is 0.6, so P(A)+Pc)= 0,6, then P(C)= 0.6-P(A)

Also, we know that team C is twice as likely to win the tournament as team D, so P(C)= 2 P(D) so P(D) = P(C)/2= (0.6-P(A))/2

Now if we use the first formula:

P(A)+P(B)+P(C)+P(D)=1

P(A)+P(A)+0.6-P(A)+(0.6-P(A))/2=1

0,5 P(A)+0.9=1

0,5 P(A)= 0,1

P(A)= 0,2

P(B)= 0,2

P(C)=0,4

P(D)=0,2

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3 years ago

If the original quantity is 10 and the new quantity is 11, what is the percent crease?

LenKa [72]

Answer:

10 %

Step-by-step explanation:

We first find change in the quantities

Then we write the change in quantity on original quantity and multiply by 100%

This implies that,

$\frac{11 - 10}{10} \times 100\%$

$=\frac{1}{10}\times100\%$

$=10\%$

Therefore the percentage increase is 10%

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Email
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3 years ago