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sleet_krkn [62]
4 years ago
6

Explain why the spectrum produced by a 1-gram sample of element Z would have the same spectral lines at the same wavelengths as

the spectrum produced by a 2gram
sample of element Z.

Chemistry
2 answers:
TEA [102]4 years ago
6 0
The reason why the spectrum produced by a 1 gram sample of element z would have the same spectral lines at the same wavelengths as the spectrum produced by a 2gram is because  Mass does not determine the spectral lines

hope this helps
Triss [41]4 years ago
6 0
Spectral lines are characteristic of an element or compound. It is an intensive property which means that it does not depend on the amount of the substance. Therefore, 1 g of Element Z will produce the same spectral lines are 2 g of Element Z.
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What is the difference between a crystalline material and an amorphous material? Give an example of each type.
Igoryamba

Answer :

As we know that there are two types of solids.

(1) Amorphous Solids

(2) Crystalline Solids

Amorphous Solids : It is a type of solids in which the constituent particles of the matter are arranged in the random manner.

That means there is no proper arrangement of atoms in solid lattice but the atoms or molecules are closely spaced that means they can move freely from one place to another.

The examples of amorphous solid are, plastics, glass, rubber, metallic glass, polymers, gel, fused silica, pitch tar, thin film lubricants, wax.

Crystalline Solids : It is a type of solids where the constituent particles of the matter are arranged in the specific manner.

That means there is a proper arrangement of atoms in solid lattice. They do not have space between the molecules or atoms and they can not move freely from one place to another.

The examples of crystalline solids are, quartz, calcite, sugar, mica, diamonds, snowflakes, rock, calcium fluoride, silicon dioxide, alum.

7 0
3 years ago
A 7.27-gram sample of a compound is dissolved in 250. grams of benzene. The freezing point of this solution is 1.02°C below that
UkoKoshka [18]

Answer:

The correct answer is 146 g/mol

Explanation:

<em>Freezing point depression</em> is a colligative property related to the number of particles of solute dissolved in a solvent. It is given by:

ΔTf = Kf x m

Where ΔTf is the freezing point depression (in ºC), Kf is a constant for the solvent and m is the molality of solution. From the problem, we know the following data:

ΔTf = 1.02ºC

Kf = 5.12ºC/m

From this, we can calculate the molality:

m = ΔTf/Kf = 1.02ºC/(5.12ºC/m)= 0.199 m

The molality of a solution is defined as the moles of solute per kg of solvent. Thus, we can multiply the molality by the mass of solvent in kg (250 g= 0.25 kg) to obtain the moles of solute:

0.199 mol/kg benzene x 0.25 kg = 0.0498 moles solute

There are 0.0498 moles of solute dissolved in the solution. To calculate the molar mass of the solute, we divide the mass (7.27 g) into the moles:

molar mass = mass/mol = 7.27 g/(0.0498 mol) = 145.9 g/mol ≅ 146 g/mol

<em>Therefore, the molar mass of the compound is 146 g/mol </em>

6 0
3 years ago
Can anyone help me part 1
valina [46]
I can help you with part 1
8 0
3 years ago
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Alex17521 [72]

Answer:

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Explanation:

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7 0
4 years ago
You have a solution of sugar water or<br> CeH720p(aq). What is the solute?<br> water<br> sugar
seropon [69]

Answer:Sugar

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4 years ago
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