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olya-2409 [2.1K]
2 years ago
9

I have made a thermometer which measures temperature by the compressing and expanding of gas in a piston. I have measured that a

t 1000 C the volume of the piston is 30 L. What is the temperature outside if the piston has a volume of 5 L? What would be appropriate clothing for the weather? I
this is about boyle’s and charles law :)))
Chemistry
1 answer:
Scrat [10]2 years ago
6 0

Answer:

The temperature is 298.5 K, which corresponds to 0.50°C.

A jacket would be appropriate clothing for this weather.

Explanation: Hope this helps:)

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For the reaction C2H4(g) + H2O(g) --> CH3CH2OH(g)
Dominik [7]

Answer : The value of equilibrium constant for this reaction at 262.0 K is 3.35\times 10^{2}

Explanation :

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy  = ?

\Delta H^o = standard enthalpy = -45.6 kJ = -45600 J

\Delta S^o = standard entropy = -125.7 J/K

T = temperature of reaction = 262.0 K

Now put all the given values in the above formula, we get:

\Delta G^o=(-45600J)-(262.0K\times -125.7J/K)

\Delta G^o=-12666.6J=-12.7kJ

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln k

where,

\Delta G^o = standard Gibbs free energy  = -12666.6 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 262.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

-12666.6J=-(8.314J/K.mol)\times (262.0K)\times \ln k

k=3.35\times 10^{2}

Therefore, the value of equilibrium constant for this reaction at 262.0 K is 3.35\times 10^{2}

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3 years ago
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Explanation:

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Heya!

HERE IS YOUR ANSWER:

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