All categories

3 years ago

Create a graphic representation that illustrates the steps from gene to protein. Label and describe each step.

Chemistry

1 answer:

Vesna [10]3 years ago

6 0

Okay so,

1) Translation- show the RNA strand attatching to a DNA strand with the complimentary base pairs. introns are spliced

2) mRNA leaves the cell and joins with a ribosome

3) Transcription - tRNA (clover shaped) reads each codon (triplets) which each code for an amino acid. The stop codons on the end tell the tRNA that the chain is finished

4) the sequence forms the primary structure (all peptide bonds) which determines the shape of the secondary (hyrdogen and peptide) and hence determines the shape of the tertiary structure of a protein (ionic, hydrogen, disulfide bridges and hydrophibic interactions)

Hope this helps :)

You might be interested in

10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C

Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

$Q=mc\Delte T$

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c = 0.385 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC$

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c = 0.903 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC$

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c = 2.42 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC$

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c = 4.18J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC$

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c = 0.128 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC$

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

3 0

4 years ago

What kind of change occurs when I’ve becomes liquid water

gregori [183]

Answer:

Its a physical

theres no chemical properties involved.

Explanation:

Brainliest please

6 0

3 years ago

This system is at equilibrium, what change would shift the equilibrium to the right?

Sidana [21]

Answer:

fjrhg

Explanation:

8 0

3 years ago

Nitrogen dioxide reacts with carbon monoxide to produce nitrogen monoxide and carbon dioxide. NO2(g) + CO(g) ⟶ NO(g) + CO2(g) A

Naya [18.7K]

<u>Answer:</u> The rate law for the reaction is $\text{Rate}=k[NO_3][CO]$

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

$NO_2(g)+CO(g)\rightarrow NO(g)+CO_2(g)$

The intermediate reaction of the mechanism follows:

Step 1: $2NO_2(g)\rightleftharpoons NO_3(g)+NO(g);\text{ (fast)}$

Step 2: $NO_3(g)+CO(g)\rightarrow NO_2(g)+CO_2(g);\text{(slow)}$

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

$\text{Rate}=k[NO_3][CO]$

Hence, the rate law for the reaction is written above.

5 0

4 years ago

Which of the following is a negatively charged particle?

kirza4 [7]

Answer:

B. electron

Explanation:

B. electron

electron is a negatively charged particle

proton is a positively charged particle

7 0

3 years ago